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Were does the graph of y equals -0.5x-2 cross the x-axis?
1.5
Where does the graph of x2 - x - 2 y cross the x-axis?
y = x^2 - x - 2 This is the graph of a parabola. We need to find the x-intercepts. Set 0 for y, and solve for x: 0 = x^2 - x - 2 0 = (x + 1)(x - 2) x + 1 = 0 or x - 2 = 0 x = -1 or x = 2 Thus, x-intercepts are -1 and 2. The graph of y = x^2 - x - 2 crosses the x-axis at x = -1 and x = 2.
An equation of the axis of symmetry of the graph y equals -x2 plus 8x-7?
y = x2 + 8x - 7 a = 1, b = 8, c = -7 the equation of the axis of symmetry: x = -b/2a x = -8/(2*1) = -4
Where does the graph of y 6x2 11x 10 cross the x-axis?
If you mean: y = 6x^2+11x-10 then x = 2/3 and x = -5/2
How many times does the graph intersect the x axis if the discriminant?
If D > 0 then the graph intersects the x-axis 2 times.If D = 0 then the the x-axis is tangent to the graph.If D < 0 then the graph doe not intersects the x-axis.
How many times does the graph of y equals x2-4x plus 4 intersect the x-axis?
y=x2-4x+4 y = (x-2)(x-2) x=2 the graph only crosses the x-axis at positive 2. this is the minimum of the graph and the only point that is crosses the x-axis.
Does a power function cross the x-axis?
Maybe it does and maybe it doesn't.Some do: y = x2 - 1 (crosses the x-axis in 2 places)and some don't: y = x2 + 1
Were does the graph of y equals -0.5x-2 cross the x-axis?
1.5
How many times will the graph of f(x) = x^2 + 9 Cross the x-axis?
It doesn't cross the x-axis since the position the equation is in is 9 units above the x-axis and the graph never curves the other way so it will never touch the x-axis
Are a polynomial's factors the values at which the graph of a polynomial meets the y-axis?
Not quite. The polynomial's linear factors are related - not equal to - the places where the graph meets the x-axis. For example, the polynomial x2 - 5x + 6, in factored form, is (x - 2) (x - 3). In this case, +2 and +3 are "zeroes" of the polynomial, i.e., the graph crosses the x-axis. That is, in an x-y graph, y = 0.
Where does the graph of x2 - x - 2 y cross the x-axis?
y = x^2 - x - 2 This is the graph of a parabola. We need to find the x-intercepts. Set 0 for y, and solve for x: 0 = x^2 - x - 2 0 = (x + 1)(x - 2) x + 1 = 0 or x - 2 = 0 x = -1 or x = 2 Thus, x-intercepts are -1 and 2. The graph of y = x^2 - x - 2 crosses the x-axis at x = -1 and x = 2.
How many times will a graph with a negative discriminant touch the y-axis?
A graph of an equation in the form y = ax^2 + bx + c will cross the y-axis once - whatever its discriminant may be.
How do you go about creating a graph with specific x intercepts like say at x equals -2 4 and 6?
If you want the graph to cross the x-axis at x = -2, then (x+2) is going to be a factor of the equation of the line. If you want the graph to cross the x-axis at x = 2 and x = 6, then the two factors will be (x-2) and (x-6) and the equation of the line will be y = (x-2)(x-6). This simplifies to y = x2-8x+12. In general, if you want to plot a graph with a line that crosses the x-axis at points x=a, x=b, x=c, x=d, ... where a,b,c,d... are integers, the equation of the line will be: y = (x-a)(x-b)(x-c)(x-d)...
What does it mean when the graph of a quadratic function crosses the x axis twice?
When the graph of a quadratic crosses the x-axis twice it means that the quadratic has two real roots. If the graph touches the x-axis at one point the quadratic has 1 repeated root. If the graph does not touch nor cross the x-axis, then the quadratic has no real roots, but it does have 2 complex roots.
An equation of the axis of symmetry of the graph y equals -x2 plus 8x-7?
y = x2 + 8x - 7 a = 1, b = 8, c = -7 the equation of the axis of symmetry: x = -b/2a x = -8/(2*1) = -4
What are the 2 types of axis on a graph?
x-axis and y-axis
Where does the graph of y-0.5x-2 cross the x-axis?
1.5
