I don't see any "following points".
Since there are no "following" points, none of them.
It has 2 solutions and they are x = 2 and y = 1 which are applicable to both equations
As Anand said, the question is vague. However, two important points for any equation are the x and y intercepts. For y = 2x, the x-intercept is (0,0) and the y-intercept is (0,0). Not sure if that helps.
This has infinite no. of solutions.
Equations can have many solutions. The equation of a straight line, for example, defines all points on the line. Even a simple equation such as x+y=5 can have a variety of solutions (x=1 when y=4, x=2 when y=3 and so on)
Yes, and no. The solution set to an inequality are those points which satisfy the inequality. A linear inequality is one in which no variable has a power greater than 1. Only if there are two variables will the solution be points in a plane; if there are more than two variables then the solution set will be points in a higher space, for example the solution set to the linear inequality x + y + z < 1 is a set of points in three dimensional space.
the solution for the inequality 4x + 2 - 6x < -1 was x < 3/2
The inequality ( y < 8 ) is represented by a horizontal line at ( y = 8 ) with a dashed line, indicating that points on the line are not included in the solution. The area below this line represents the solution set, where all points have a ( y )-value less than 8. Therefore, any graph depicting this with the correct shading below the dashed line would accurately represent the inequality.
y > 5x - 2 y < 5x + 3 A.(4, 20) B.(-5, 25) C.(5, 28) D.(4, 23)
Graphing inequalities on a grid involves first translating the inequality into an equation to determine the boundary line. For example, for the inequality (y < 2x + 3), you would graph the line (y = 2x + 3) as a dashed line (indicating that points on the line are not included). Next, you select a test point (usually the origin, if it’s not on the line) to determine which side of the line to shade. The shaded region represents all the solutions to the inequality.
To graph linear inequalities, you first identify the boundary line by rewriting the inequality in slope-intercept form (y = mx + b) and plotting the corresponding linear equation. If the inequality is strict (e.g., < or >), you use a dashed line to indicate that points on the line are not included. For non-strict inequalities (e.g., ≤ or ≥), a solid line is used. Finally, you shade the appropriate region of the graph to represent the solutions that satisfy the inequality, based on whether the inequality is greater than or less than.
To graph the inequality ( y + 2 > -3(x + 1) ), first, rearrange it to isolate ( y ): ( y > -3x - 3 - 2 ), which simplifies to ( y > -3x - 5 ). This represents a straight line with a slope of -3 and a y-intercept of -5. Since the inequality is strict (greater than), you would draw a dashed line for ( y = -3x - 5 ) and shade the region above the line to indicate all the points that satisfy the inequality.
(1,2) (0,5) (-1,8) (2,-1) (-2,11) All of these are solutions to the given equation.
1
There are no common points for the following two equations: y = 2x + 3 y = 2x - 1 If you graph the two lines, since they have the same slope, they are parallel - they will never cross.
Since there are no "following" points, none of them.
It has 2 solutions and they are x = 2 and y = 1 which are applicable to both equations