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The solutions to a linear inequality are the points in the plane that make the inequality true?

Yes, and no. The solution set to an inequality are those points which satisfy the inequality. A linear inequality is one in which no variable has a power greater than 1. Only if there are two variables will the solution be points in a plane; if there are more than two variables then the solution set will be points in a higher space, for example the solution set to the linear inequality x + y + z < 1 is a set of points in three dimensional space.


Check all of the points that are solutions to the system of inequalities y 4x plus 3 y -4x plus 6?

the solution for the inequality 4x + 2 - 6x < -1 was x < 3/2


What points are solutions to the system of inequalities shown below y6x 7 y6x 9?

To determine the points that are solutions to the system of inequalities (y \leq 6x + 7) and (y \geq 6x + 9), we need to analyze the area between the two lines represented by these inequalities. The first inequality represents a region below the line (y = 6x + 7), while the second represents the region above the line (y = 6x + 9). Since the two lines are parallel, there are no points that satisfy both inequalities simultaneously; thus, there are no solutions to the system.


Which of the following points are solutions to the system of inequalities shown below?

y > 5x - 2 y < 5x + 3 A.(4, 20) B.(-5, 25) C.(5, 28) D.(4, 23)


What graph correctly represents the inequality y 8?

The inequality ( y &lt; 8 ) is represented by a horizontal line at ( y = 8 ) with a dashed line, indicating that points on the line are not included in the solution. The area below this line represents the solution set, where all points have a ( y )-value less than 8. Therefore, any graph depicting this with the correct shading below the dashed line would accurately represent the inequality.


How do graph inequalities on a grid?

Graphing inequalities on a grid involves first translating the inequality into an equation to determine the boundary line. For example, for the inequality (y &lt; 2x + 3), you would graph the line (y = 2x + 3) as a dashed line (indicating that points on the line are not included). Next, you select a test point (usually the origin, if it’s not on the line) to determine which side of the line to shade. The shaded region represents all the solutions to the inequality.


What is the points where used to graph linear inequalities?

To graph linear inequalities, you first identify the boundary line by rewriting the inequality in slope-intercept form (y = mx + b) and plotting the corresponding linear equation. If the inequality is strict (e.g., &lt; or &gt;), you use a dashed line to indicate that points on the line are not included. For non-strict inequalities (e.g., ≤ or ≥), a solid line is used. Finally, you shade the appropriate region of the graph to represent the solutions that satisfy the inequality, based on whether the inequality is greater than or less than.


Which of thw following points are on the line given by the equation y equals -3x plus 5?

(1,2) (0,5) (-1,8) (2,-1) (-2,11) All of these are solutions to the given equation.


Find the graph of the inequality y plus 2 and gt -3(x plus 1).?

To graph the inequality ( y + 2 &gt; -3(x + 1) ), first, rearrange it to isolate ( y ): ( y &gt; -3x - 3 - 2 ), which simplifies to ( y &gt; -3x - 5 ). This represents a straight line with a slope of -3 and a y-intercept of -5. Since the inequality is strict (greater than), you would draw a dashed line for ( y = -3x - 5 ) and shade the region above the line to indicate all the points that satisfy the inequality.


Why The equation y and ndashx plus 4 is the boundary line for the inequality y?

The equation ( y = -x + 4 ) represents a linear boundary line in a two-dimensional coordinate plane. The inequality ( y &lt; -x + 4 ) indicates that we are interested in the region below this line. The line itself is not included in the solution set, as indicated by the strict inequality, which distinguishes the boundary from the solutions. Thus, the boundary line serves as a critical demarcation for the area that satisfies the inequality.


What points are NOT on the graph of y x2 - 1?

1


Are there any solutions to the system of inequalities y equals 2x plus 3 and y equals 2x - 1?

There are no common points for the following two equations: y = 2x + 3 y = 2x - 1 If you graph the two lines, since they have the same slope, they are parallel - they will never cross.