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In some simple cases, factoring allows you to find solutions to a quadratic equations easily.

Factoring works best when the solutions are integers or simple rational numbers. Factoring is useless if the solutions are irrational or complex numbers. With rational numbers which are relatively complicated (large numerators and denominators) factoring may not offer much of an advantage.

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Q: Why is factoring a valuable tool for solving quadratic equations?
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When solving a quadratic equation by factoring what method is used?

Start with a quadratic equation in the form � � 2 � � � = 0 ax 2 +bx+c=0, where � a, � b, and � c are constants, and � a is not equal to zero ( � ≠ 0 a  =0).

Solving quadratic equations by factoring?

(k + 1)(k - 5)= 0

Can all quadratics be solved by completing the square?

Completing the square is one method for solving a quadratic equation. A quadratic equation can also be solved by factoring, using the square roots or quadratic formula. Solving quadratic equations by completing the square will always work when solving quadratic equations-You can also use division or even simply take a GCF, set the quantities( ) equal to zero, and subtract or add to solve for the variable

How many methods are there for solving quadratic equations?

There are several methods for solving quadratic equations, although some apply only to specific quadratic equations of specific forms. The methods include:Use of the quadratic formulaCompleting the SquareFactoringIterative methodsguessing

What does quadratic equations using the factoring method means?

It means you are required to "solve" a quadratic equation by factorising the quadratic equation into two binomial expressions. Solving means to find the value(s) of the variable for which the expression equals zero.

Which the easy way the method of factoring or the solving the quadratic equation?

By knowing how to use the quadratic equation formula.

Can Quadratic equations that can be solved using the quadratic formula also be solved by factoring?

Yes, however not all quadratic equations can easily be solved by factoring, sometimes you can factor and sometimes it is easier to use the quadratic formula. Example: x2 + 4x + 4 This can be easily factored to (x + 2)(x +2) Therefore the answer is -2 by setting x +2 = 0 and solving for x This can be done using the quadratic equation and you would get the same results, however, it was much faster to factor instead.

What are the best on-line calculators for solving quadratic equations by using the quadratic formula?

When must the quadratic formula be used in algebra?

You'll typically use it when solving a quadratic equation - when factoring isn't obvious.

What form is the solving for the roots of quadratic equations?

Using the quadratic equation formula or completing the square

What is the third step in solving this equation by completing the square?

Completing the square is one method for solving a quadratic equation. A quadratic equation can also be solved by several methods including factoring, graphing, using the square roots or the quadratic formula. Completing the square will always work when solving quadratic equations and is a good tool to have. Solving a quadratic equation by completing the square is used in a lot of word problems.I want you to follow the related link that explains the concept of completing the square clearly and gives some examples. that video is from brightstorm.

Can all quadratic equations be solved?

Well, that depends on what you mean "solve by factoring." For any quadratic equation, it is possible to factor the quadratic, and then the roots can be recovered from the factors. So in the very weak sense that every quadratic can be solved by a method that involves getting the factors and recovering the roots from them, all quadratic equations can be solved by factoring. However, in most cases, the only way of factoring the quadratic in the first place is to first find out what its roots are, and then use the roots to factor the quadratic (any quadratic polynomial can be factored as k(x - r)(x - s), where k is the leading coefficient of the polynomial and r and s are its two roots), in which case trying to recover the roots from the factors is redundant (since you had to know what the roots were to get the factors in the first place). So to really count as solving by factoring, it makes sense to require that the solution method obtains the factors by means that _don't_ require already knowing the roots of the polynomial. And in this sense, most quadratic equations are not solvable through factoring.