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The log is the answer to the question, "To what power must I raise a number (the base) to obtain a certain other number?" In this case (assuming a base 10), you are looking for the solution to the equation 10x = 1. The answer, of course, is x = 0.

The reason it is "of course" is because 10x divided by 10x ie 1, is found by subtracting the powers (which are logarithms) to give 100

Q: Why is the log of 1 equal to 0?

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the definition of log N = X is 10 to the X power =N for log 0 we have 10 to the x power = 0 The solution for x is that x is very large (infinite) and negative, that is, minus infinity As N gets smaller and smaller, log N approaches minus infinity log 1 = 0 log .1 = -1 log .001 = -3 log .000001 = -6 log 0 = -infinity

Here are a few, note x>0 and y>0 and a&b not = 1 * log (xy) = log(x) + log(y) * log(x/y) = log(x) - log(y) * loga(x) = logb(x)*loga(b) * logb(bn) = n * log(xa) = a*log(x) * logb(b) = 1 * logb(1) = 0

log 1 = 0 if log of base 10 of a number, N, is X logN = X means 10 to the X power = N 10^x = 1 x = 0 since 10^0 = 1

We know that a logarithm is an exponent. Let x^8 = a. For x > 0, x is different than 1, and a > 0, x^8 = a is equal to the log with base x of a = 8

Log x is defined only for x > 0. The first derivative of log x is 1/x, which, for x > 0 is also > 0 The second derivative of log x = -1/x2 is always negative over the valid domain for x. Together, these derivatives show that log x is a strictly monotonic increasing function of x and that its rate of increase is always decreasing. Consequently log x is convex.

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with something called logarithms. So 1 = (1 + x)^5 log 1 = log ((1+x)^5) log 1 = 5 x log (1 +x) but log 1 = 0 therefore 0 = 5 x log(1+x) divide both sides by 5 and you get 0 = log (1+x) we know that log 1 = 0, therefore 1+ x = 1 and so x = 0

1

the definition of log N = X is 10 to the X power =N for log 0 we have 10 to the x power = 0 The solution for x is that x is very large (infinite) and negative, that is, minus infinity As N gets smaller and smaller, log N approaches minus infinity log 1 = 0 log .1 = -1 log .001 = -3 log .000001 = -6 log 0 = -infinity

acording to me the value is 0 because the value of log 1 at any base is always 0.

Here are a few, note x>0 and y>0 and a&b not = 1 * log (xy) = log(x) + log(y) * log(x/y) = log(x) - log(y) * loga(x) = logb(x)*loga(b) * logb(bn) = n * log(xa) = a*log(x) * logb(b) = 1 * logb(1) = 0

The pH is define in the following way: pH = -log [H+] What that means is the pH is the negative of the base 10 logarithm of the concentration of hydrogen ions in the solution. So, if you have a pH = 0, that means that the concentration of H+ is equal to 1 molar, because -log(1) = 0. If you have a 1 M solution of any strong acid, the pH will be equal to zero.

log 1 = 0 if log of base 10 of a number, N, is X logN = X means 10 to the X power = N 10^x = 1 x = 0 since 10^0 = 1

log(0) is not defined, so the first part of the question cannot be answered.log(5) = 0.6990 and log(1) = 0 so the reduction is 0.6990log(0) is not defined, so the first part of the question cannot be answered.log(5) = 0.6990 and log(1) = 0 so the reduction is 0.6990log(0) is not defined, so the first part of the question cannot be answered.log(5) = 0.6990 and log(1) = 0 so the reduction is 0.6990log(0) is not defined, so the first part of the question cannot be answered.log(5) = 0.6990 and log(1) = 0 so the reduction is 0.6990

Log(3 * 1/3) = log(1) = 0

No, 1 is not equal to 0. 0 is equal to 0 and 1 is equal to 1.

We know that a logarithm is an exponent. Let x^8 = a. For x > 0, x is different than 1, and a > 0, x^8 = a is equal to the log with base x of a = 8

(2 - 1) * 0 = 0 Thus 2 - 1 = 0/0 = 0 and therefore 2 = 1