Given vectors A and B, the cross product C is defined as the vector that
1) is perpendicular to both A and B (which is what you are looking for)
2) whose magnitude is the product of the magnitudes of A and B times the sine of the angle between them.
If we write the three elements of A as A(1) A(2) A(3), and the same for B, then the components of C are
C(1)=A(2)*B(3)-A(3)*B(2);
C(2)=A(3)*B(1)-A(1)*B(3);
C(3)=A(1)*B(2)-A(2)*B(1);
A perpendicular vector is a vector that forms a right angle (90 degrees) with another vector in a given space. This means that the dot product of two perpendicular vectors is zero, indicating that they are orthogonal to each other.
The component of a vector x perpendicular to the vector y is x*y*sin(A) where A is the angle between the two vectors.
I think you meant to ask for finding a perpendicular vector, rather than parallel. If that is the case, the cross product of two non-parallel vectors will produce a vector which is perpendicular to both of them, unless they are parallel, which the cross product = 0. (a zero vector)
The zero vector is both parallel and perpendicular to any other vector. V.0 = 0 means zero vector is perpendicular to V and Vx0 = 0 means zero vector is parallel to V.
One physical example of a vector perpendicular to its derivative is angular momentum in the case of rotational motion. The angular momentum vector is perpendicular to the angular velocity vector, which is the derivative of the angular displacement vector. Another example is velocity and acceleration in circular motion, where velocity is perpendicular to acceleration at any given point on the circular path.
The Resultant Vector minus the other vector
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The zero vector is not perpendicular to all vectors, but it is orthogonal to all vectors.
Divide the vector by it's length (magnitude).
No, the velocity vector of a charged particle is not affected by the electric field if it is perpendicular to the field. The electric force acting on the particle is zero in this case because the force is given by the product of charge and the component of electric field parallel to the velocity vector.
That is not even true!
No, the curl of a vector field is a vector field itself and is not required to be perpendicular to every vector field f. The curl is related to the local rotation of the vector field, not its orthogonality to other vector fields.