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Q: Does every real numbers have a multiplicative inverse?

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All rational numbers, with the exception of zero (0), have a multiplicative inverse. In fact, all real numbers (again, except for zero) have multiplicative inverses, though the inverses of irrational numbers are themselves irrational. Even imaginary numbers have multiplicative inverses (the multiplicative inverse of 5i is -0.2i - as you can see the inverse itself is also imaginary). Even complex numbers (the sum of an imaginary number and a real number) have multiplicative inverses (the inverse of [5i + 2] is [-5i/29 + 2/29] - similar to irrational and imaginary numbers, the inverse of a complex number is itself complex). The onlynumber, in any set of numbers, that does not have a multiplicative inverse is zero.

The same as for a real number: 1 divided by the number.For example, the multiplicative inverse (or reciprocal) of 2i is 1 / 2i = -(1/2)i.

Rational numbers and Real Numbers. The multiplicative inverses of integers are not integers.

It is 1, as it is for all complex numbers - which includes real numbers.

So if you have a number z = a + bi. Then how to find 1 divided by z. The way to figure this is to get the denominator as a pure real number. Multiplying the numerator and the denominator by the complex conjugate {a - bi} will result in a pure real denominator.(a - bi)(a + bi) = aÂ² + abi - abi - (bi)Â² = aÂ² + bÂ². So the multiplicative inverse is(a - bi)/(aÂ² + bÂ²)

Related questions

The only real (or complex) number which does not have a multiplicative inverse is 0. There is nothing you can multiply by 0 to get 1.

All rational numbers, with the exception of zero (0), have a multiplicative inverse. In fact, all real numbers (again, except for zero) have multiplicative inverses, though the inverses of irrational numbers are themselves irrational. Even imaginary numbers have multiplicative inverses (the multiplicative inverse of 5i is -0.2i - as you can see the inverse itself is also imaginary). Even complex numbers (the sum of an imaginary number and a real number) have multiplicative inverses (the inverse of [5i + 2] is [-5i/29 + 2/29] - similar to irrational and imaginary numbers, the inverse of a complex number is itself complex). The onlynumber, in any set of numbers, that does not have a multiplicative inverse is zero.

All real numbers, except 0, have a multiplicative inverse. For any real x, (x not = 0), there exists a real number y such that x*y = 1. This y is denoted by 1/x.

A multiplicative inverse for 2 numbers exists if the 2 numbers are coprime, i.e. their greatest common divisor (or gcd) is 1. However, if your question refers to just a singular number, virtually all real numbers (with the exception of zero) have a multiplicative inverse.

Every non zero number has a multiplicative inverse, which is 1 divided by that number. This stands for both real and complex numbers. This can be proved by letting x=some non zero number. x*(1/x)=x/x=1, therefore the multiplicative inverse of x is 1/x.

For every real number, x, which is not zero, there exists a real number x' such that x * x' = x' * x = 1, the multiplicative identity.

On the set of all real numbers ZERO has no multiplicative inverse. For other sets there may be other numbers too, so please define your set!

No, it is not true.

The additive inverse is the inverse under addition; the multiplicative inverse is the inverse under multiplication. For example, the additive inverse of any real or complex number is its negative: the inverse of 3 is -3 and vice versa. The multiplicative inverse of a number other than 0 (which has no such inverse) is its reciprocal: the inverse of 2 is 1/2, and vice versa. Adding a number and its additive inverse gives the additive identity, 0. Multiplying a number by its multiplicative inverse gives the multiplicative identity, 1.

Yes. That's basically the definition of a multiplicative inverse.Also, this doesn't only apply to fractions - it applies to any real numbers.

1

That number is zero. It has no inverse because there is no number that you can multiply by zero to get one; to put this another way; The equation 0x= 1 has no solution, bacause 0x = 0 for all real numbers x.

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