The factors are -1(2x + 1)(3x + 4)
If the question could more exactly be phrased as, "What is the value of x when 9x2 - 16 = 0", the answer is, x = 4 or -4. This answer can be found by factoring 9x2 - 16 into (3x + 4)(3x - 4) and setting each factor equal to zero.
(x - 8)(3x + 4)
The sum of the coefficients is 3 - 7 + 4 = 0 so (x - 1) is a factor. Thus, 3x2 - 7x + 4 = 3x2 - 3x - 4x + 4 = 3x(x - 1) - 4(x - 1) = (3x - 4)(x - 1)
(x2 + 3x + 5)(x2 - 3x + 4)
The factors are -1(2x + 1)(3x + 4)
2(5x - 1)(3x - 2)
It is: (3x+4)(2x-3) when factored
3x^2+3x-60=3(x^2+x+20)=3(x+5)(x-4)
(3x-4)(3x+4)
(x+4)(x-7)
7
3x2 -14x -24 can be factored as (3x + 4)(x - 6).
Your factors must begin 3x and x to give 3x2. The factors of 12 are 1/12, 2/6 and 3/4. Which pair, together with 3x and x, can add to -5? 3 and 4 seem to fit the bill: (3x + 4)(x - 3)
If the question could more exactly be phrased as, "What is the value of x when 9x2 - 16 = 0", the answer is, x = 4 or -4. This answer can be found by factoring 9x2 - 16 into (3x + 4)(3x - 4) and setting each factor equal to zero.
9x2 + 27x - 36 = 9(x2 + 3x - 4) = 9(x + 4)(x - 1)
(x - 8)(3x + 4)