(9x - 1)(9x - 1)
Divide all terms by 3 and it is: (2x-1)(x+2)
You can find the prime factorization of 130: 130 = 2*5*13 Therefore the answer is 1. Or you can skip a step. Just divide 130 by 2. You get 65, which is an odd number. Therefore there is only 1 factor of 2 in the factorization of 130.
prime factorization of 89: 1 and 89
Factors for 32 are: 1, 2, 4, 8, 16, 32 Prime Factors: 2 Prime Factorization: 2* 2 * 2 * 2 * 2 or 25
To find the greatest common factor (GCF) of 112, 56, and 85, we first need to find the prime factorization of each number. The prime factorization of 112 is 2^4 * 7, the prime factorization of 56 is 2^3 * 7, and the prime factorization of 85 is 5 * 17. To find the GCF, we identify the common prime factors and multiply them together. In this case, the GCF of 112, 56, and 85 is 7.
x2 - 6x + 5 = (x - 1)(x - 5)
2(x + 1)(2x + 1)
(x + 4)(x + 1)
8(1 + 4g)
6x(1+4)
(11x - 1)(11x - 1) (11x - 1)2
(x + 2)(3x + 1)
(x-6)(x+1)
4x2 + 12x + 5 = (2x + 1)(2x + 5).
3x2 + 10x + 3 = (x + 3)(3x + 1).
5x2 + 9x + 4 = (x + 1)(5x + 4).
(y + 30)(y - 1)