3x+21x+9x=33x. Break it apart. The factor of x is x and the factors of 33 are 3 and 11. Therefore, the factors of 3x+21x+9x are 3, 11, and x.
i hope you mean (2x^2 + 21x + 49) you cant solve it its already in its lowest possible form
7(3x+7)
The answer will be 21x + 1
(2x+7)(x+7)
3x+21x+9x=33x. Break it apart. The factor of x is x and the factors of 33 are 3 and 11. Therefore, the factors of 3x+21x+9x are 3, 11, and x.
It is: 3x*(x+7)
(2x - 1)(x - 10)
(x - 8)(x - 13)
(5x-6)(x-3)
21x + 12x -2 = 0 33x -2 = 0 33x = 2 x = 2/33 x = 0.06
3x2-21x+36 =3(x2-7x+12) =3(x-4)(x-3)
I'm assuming that your solving for X. 21x + 12x - 2 = 0 33x - 2 = 0 33x = 2 x = 2/33 x =.06
To factor the expression 21x^35, you need to find the common factors of 21 and x^35. The factors of 21 are 1, 3, 7, and 21. The factors of x^35 are x, x^2, x^3, ..., x^35. Therefore, the factored form of 21x^35 is 21x*x^34 or 21x^(35-1).
2x2+21x+49 = (2x+7)(x+7)
21x + 9 = 180 21x = 180 - 9 21x = 171 x = 171/21 x = 8.143
(2x+3)/(10x2+21x+9)Factor the quadratic expression in the denominator:(2x+3)/(5x+3)(2x+3)which becomes:1/(5x+3) or (5x+3)-1