The greatest common factor (GCF) is 7.
3(7x-6)
7(3x plus or minus 5) depending on the missing sign.
Y³-4y²-12y = y(y - 6)(y + 2) 3x³+30x²+75x = 3x(x + 5)2 5yto5-80y³ = 5y3(y + 4)(y - 4) 24to5-18y³ = 6y3(4y2 - 3) 25x to the 6th - 64 = (5x3 + 8)(5x3 - 8) 27xt³+343 = (3x + 7)(9x2 - 21x + 49) X³-64 = (x - 4)(x2 + 4x + 16)
Let the 2 numbers be x and y then we have x+y = 21 y = 21 - x ......(1) Also given that xy = 98 plug in y from (1) x(21-x) = 98 21x - x² = 98 x² - 21x + 98 = 0 x² - 14x - 7x + 98 = 0 x(x-14) - 7(x - 14) = 0 (x-14)(x-7) = 0 x = 14 or x = 7 If x = 14 then y =21-14 = 7 If x=7, then y = 21-7 = 14 So the two numbers are 7 and 14
The greatest common factor (GCF) is 7.
It is: 3x*(x+7)
Make it equal zero by subtracting 21x from both sides. 20x2 - 21x - 5 factors to (4x - 5)(5x + 1)
3x2-21x+36 =3(x2-7x+12) =3(x-4)(x-3)
To factor 4x^2 - 21x + 5, we look for two binomials in the form (Ax + B)(Cx + D) that multiply to give 4x^2 - 21x + 5. We can determine the values of A, B, C, and D by examining the factors of 4 and 5. The factored form is then (4x - 1)(x - 5).
3x+21x+9x=33x. Break it apart. The factor of x is x and the factors of 33 are 3 and 11. Therefore, the factors of 3x+21x+9x are 3, 11, and x.
(2x+3)/(10x2+21x+9)Factor the quadratic expression in the denominator:(2x+3)/(5x+3)(2x+3)which becomes:1/(5x+3) or (5x+3)-1
3(7x-6)
3(7x + 11)
Assuming that it is only the x that is being squared. (-21x^2)/39 = (-7x^2)/13
gcf(35x², 7xy², 21x²y²) = 7x 35x² = 5 times 7 times x² 7xy² = 7 times x times y² 21x²y² = 3 times 7 times x² times y² hcf = 7 times x = 7x (I've written the multiplication as times instead of using the × symbol to avoid confusion with the unknown x.)
(2x - 1)(x - 10)