Look for something which you can divide both terms by. In this case both 3x and 15 are divisible by 3, so put this outside of a bracket and write the two terms divided by the common factor inside the bracket. So the answer is 3(x+5).
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3(3x + 5)
3(x2 + 3x + 1)
3 is a factor and dividing by 3 gives x + 15 = 8x
3x2 + 10x + 3 = (x + 3)(3x + 1).
9x2 + 6x + 1 = 9x2 + 3x + 3x + 1 = 3x(3x + 1) + 1(3x + 1) = (3x + 1)(3x + 1) or (3x +1)2