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Since the third term is negative, you need a positive and a negative factor, like this:
(n + ...) (n - ...)
Find two numbers that, when multiplied, give 72, and whose difference is 14. Just try the different factors of 72. If that doesn't work, use the quadratic formula. (Hint: it does work, in this case.)
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In which situation would you factor out -1 from a trinomial?
You would factor out -1 (a) from a trinomial in an equation such as -a^2 +30a - 2a + 60 after the middle term has been separated. The final answer of this trinomial would then be (a-30) (a-30).
Which of the binomials below is a factor of this trinomial x2-10x-39?
The factors of that trinomial are (x - 13) and (x + 3) . Neither of them appears below.
How do you factor a trinomial with a leading coefficient is equal to 1?
Suppose the trinomial is x2 + Bx + C You need to find a factor pair of C whose sum is B. If the factors are p and q (that is, pq = C and p+q = B), then the trinomial can be factorised as (x + p)*(x + q).
What is the factor of the trinomial x2 - 3x - 4?
(x + 1)(x - 4)
Factor the trinomial x2 plus 2x - 24?
(x+6)*(x-4)
