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You can't.
x4 + y4 is irreducible.
It's (x+yi^1.5)(x+yi^0.5)(x-yi^1.5)(x-yi^0.5). You use the equation x^2-y^2=(x+y)(x-y) and x^2+y^2=(x+yi)(x-yi).
*Edit This IS reducible.
X^4+Y^4=X^4+Y^4+2X^2Y^2 -2X^2Y^2 I add and minus 2X^2Y^2 so the value stays the same.
X^4+Y^4+2X^2Y^2=(X^2+Y^2)^2
So it equals to (X^2+Y^2)^2-2X^2Y^2.
Then, we factor using difference of squares.
(X^2+Y^2)^2-2X^2Y^2=(X^2+Y^2+sqrt2 XY)(X^2+Y^2-sqrt2 XY)
*Note the XY is not included in the sqrt sign
To factor x^4 + y^4, we can use the formula for the sum of fourth powers: a^4 + b^4 = (a^2 + b^2)(a^2 - ab + b^2). Therefore, x^4 + y^4 can be factored as (x^2 + y^2)(x^2 - xy + y^2). This is the final factored form of x^4 + y^4.
(x ^ 2 + y ^ 2) ^ 2 - 2 * (x ^ 2 * y ^ 2)
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What is factor x4-4x3-12x2-32x plus 64?
x4 - 4x3 - 12x2 -32x + 64 (x - 4)(x + 2)(x + 2)(x - 4)
How do you factor x4 plus 4x3-7x-34x-24?
(x - 3)(x + 1)(x + 2)(x + 4)
What is the Greatest Common Factor of x4 and x3?
Greatest common factor of x4 and x3 is x3.
How do you factor y4-256?
(y - 4)(y + 4)(y^2 + 16)
How do you factor completely over the set of polynomials with integral coefficients x4-4x3 plus 14x2-4x plus 13?
(x^2 + 1)(x^2 - 4x + 13)
X2 plus y4 plus x4 plus y2?
x2 + y4 + x4 +y2 = x6 + y6unless you know what x and y are.* * * * *x2 + y4 + x4 + y2 ??I don't believe that this expression can be factorised or otherwise simplified.It certainly does not equal x6 + y6,for all x and all y:for example, if x = y = 1, thenx2 + y4 + x4 + y2 = 4, whilstx6 + y6 = 2;thus, they are two manifestly unequal quantities.
How can you do x4-y4?
(x2 + y2)(x + y)(x - y) = x4 - y4.
X4 plus y4 divided by x plus y?
(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)
What is the square root of 100 x4 y4?
sqrt(100x4y4) = sqrt(100)*sqrt(x4)*sqrt(y4) = 10*x2*y2
What is the greatest common factor of x4 y4 x10 y6 x9 x4?
18xy is the GCF of 72x2y and 18xy
How do you express x4 plus y4 if given x plus y equals a xy equals b?
(x + y)2 = x2 + 2xy + y2 So x2 + y2 = (x + y)2 - 2xy = a2 - 2b Then (x2 + y2)2 = x4 + 2x2y2 + y4 So x4 + y4 = (x2 + y2)2 - 2x2y2 = (a2 - 2b)2 - 2b2 = a4 - 4a2b + 4b2 - 2b2 = a4 - 4a2b + 2b2
What is the factor of Y4 plus 10y2 plus 16?
(y^2 + 8)(y^2 + 2)
What is the answer for x plus y to 4th power?
(x+y)4 = (x2+2xy+y2)2 = x4+4x3y+6x2y2+4xy3+y4
Factor completely 32y4 -2x4 y4?
2y4(16 - x4) = 2y4 (4 + x2)(4 - x2) = 2y4(4 + x2)(2 + x)(2 - x)
Can you please help me factor x4 plus 4y8?
It is: 1(x4+4y8) and can't be factored any further
What is y plus y plus y plus y?
y4.
What is factor x4-4x3-12x2-32x plus 64?
x4 - 4x3 - 12x2 -32x + 64 (x - 4)(x + 2)(x + 2)(x - 4)
