x^(2) - 12x + 36
Look for two factors of '36', that add/subtract to '12'. ;-
1,36 ; 2,18; 4,9; 6,6.
The last pair 6 & 6 add to ;12;
Hence
(x 6 )(x 6)
Which signs????
Since '36' is positive(+), then both the signs are the same. They can be both negative , or both positive.
Since the sign in '12x' is hegative then they are both negative.
Hence
(x - 6)(x - 6) Done!!!!!
(x + 12)(x - 3)
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (5 plus or minus the square root of 73) divided by 12. y = 1.128666978776461 y = -0.2953336454431275
x2-10x-24 = (x+2)(x-12) when factored
There is a formula for the difference of squares. If that's x2 - 144, the answer is (x - 12)(x + 12)
3(3z + 4)
(x + 12)(x - 3)
(x - 5)(x + 12)
(6x - 1)(6x - 1)
It is x^2 -13x +12 = (x-1)(x-12) when factored
The expression x2 + 1x - 12 can be factored out as (x - 3)(x + 4)
x2+2x-120 = (x+12)(x-10) when factored
133
(n - 4)(n - 12)
x2 + x - 12 = (x + 4) (x - 3)
(x - 4)(x - 3)
(2x - 4)(2x + 3) The key is to look for all the factor pairs of 12.
Find out what two numbers add up to -8 yet when mutiplied they produce 12 and so: x squared-8x+12 = (x-2)(x-6) when factored