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How many positive integers less than 1000 have distinct digits and are even?
To determine the number of positive integers less than 1000 with distinct digits and are even, we need to consider the possible combinations of digits. Since the number must be even, the last digit must be even, giving us 5 options (0, 2, 4, 6, 8). For the hundreds digit, we have 9 options (1-9), and for the tens digit, we have 8 options (0-9 excluding the hundreds digit and the last digit). Therefore, the total number of such integers is 5 * 9 * 8 = 360.
How many number between 1000 and 9999 in which all the integers are even?
Oh, dude, you're talking about four-digit numbers where every digit is even, right? So, we've got 2, 4, 6, and 8 to play with. Each place can have any of those four options, so it's like 4 choices for each of the 4 digits. That's 4x4x4x4, which is 256 numbers between 1000 and 9999 where all the digits are even.
How do you write 345 as a decimal?
To write 345 as a decimal, you place the decimal point after the last digit. So, 345 written as a decimal is 345.0. This is because the decimal point is always placed after the whole number part, even if there are no decimal digits.
Why the greatest 2 digit even number is 98?
Because the next greater even number is 100. That, and any subsequent even number, consists of three or more digits.
What is 120 in a decimal?
A decimal number is simply a way of representing a number in such a way that the place value of each digit is ten times that of the digit to its right. A decimal representation does not require a decimal point. So the required decimal representation is 120, exactly as in the question.
