(X^2) + 4 = 0
(X^2) = -4
X = +/- 2i
(X+2i)(X-2i)
This can't be factorised easily. The above method is the factorisation for (X^2) - 4,
and is also the difference of two squares (9-4) = (3+2)(3-2) etc...
(x - 8)(x - 4)
The GCF is 4.
The factors are -1(2x + 1)(3x + 4)
x(x-4)
It is the difference of squares. (x-4) and (x+4) <--- answer
(a + 2 - b) (a + 2 + b)
4(x+y)^2
9x^(2) + 16 DOES NOT factor. Remember ; two squared terms with a plus(+) between them DOES NOT factor However, two squared terms with a minus(-) between them DOES factor . Hence 9x^(2) + 16 = (3x)^2) + 4^(2) does NOT factor However, 9x^(2) - 16 = (3x)^2) - 4^(2) does factor to ( (3x - 4)(3x + 4) Note the two different signs.
13
(b + 4)(b + 4)
Factor it out: (x+2) squared
(3x - y+ 2)(3x + y + 2)
(2x+3)(2x+4)
(b + 8)(b + 4)
(3+2) (4+48)
2(x^2 + 2)
(x-1)(x-4)