(X^2) + 4 = 0
(X^2) = -4
X = +/- 2i
(X+2i)(X-2i)
This can't be factorised easily. The above method is the factorisation for (X^2) - 4,
and is also the difference of two squares (9-4) = (3+2)(3-2) etc...
(x - 8)(x - 4)
The GCF is 4.
The factors are -1(2x + 1)(3x + 4)
x(x-4)
It is the difference of squares. (x-4) and (x+4) <--- answer
(a + 2 - b) (a + 2 + b)
4(x+y)^2
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
(b + 4)(b + 4)
Factor it out: (x+2) squared
13
(3x - y+ 2)(3x + y + 2)
(2x+3)(2x+4)
(3+2) (4+48)
(b + 8)(b + 4)
2(x^2 + 2)
(x-1)(x-4)