Yes, but not evenly.
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To determine if 65483 is divisible by a certain number, you would typically divide 65483 by that number and check if the remainder is zero. 65483 divided by 2 has a remainder, so it is not divisible by 2. 65483 divided by 3 also has a remainder, so it is not divisible by 3. However, 65483 divided by 7 gives a remainder of 0, so it is divisible by 7.
Suppose x = sqrt(3*a) where a is an integer that is not divisible by 3. then x2 = 3*a which is divisible by 3. but x is not even rational and so is not an integer and is certainly not divisible by 3.
12345 is divisible by 3 and the answer is 4115
Well, to find out if any number is divisible by 3, you add up the number's factors. If the number you come up with is divisible by 3, then the entire number is divisible by 3.For example:138= 1+3+8= 1212 is divisible by 3.
To determine if 42 is divisible by 3, you can add up the digits of 42 (4 + 2 = 6) and check if the sum is divisible by 3. Since 6 is divisible by 3, then 42 is also divisible by 3. This is based on the rule that a number is divisible by 3 if the sum of its digits is divisible by 3.