ok this is what it looks like to me...I definitely could be wrong. one integer is three more than twice another integer if one integer is three more than another number (x+3=y) Then you just multiply "the other number" by 2. (x+3=2*y) Sum of two integers is 36....so add them (x+y=36) Solve that equation for one number so...(y=36-x) Then you would plug that equation into the first equation where there is a y: (x + 3 = 2*(36-x))
51
The sum of three negative integers is always negative.
The integers are 5 and 7.
9,11,13
It cannot be done. The basic rules of math. odd integer plus odd integer = even integer. odd integer plus even integer = odd integer. Always. odd integer plus odd integer plus odd integer = odd integer. Always.
That has no integer solution. Three times an integer is another integer; if you subtract to integers, you get an integer again, not a fraction.
The sum of three consecutive integers is -72
This would be impossible - since the mean of the three integers would have to be an integer, and if you divide -56 by 3, you do not get an integer.
51
Suppose the smaller integer is x, then the larger one is x+1. x + 3*(x+1) = 43 That is x + 3x + 3 = 43 so that 4x = 40 and that implies that x = 10 and so the other integer is 11.
Let the smaller integer be x, then then larger integer is x + 2, and: 3x + (x + 2) = 58 → 4x = 56 → x = 14 → The two integers are 14 and 16.
The sum of three negative integers is always negative.
They are 14, 16 and 18.
The numbers are 14, 16 and 18.
You can find this by dividing 2010 by three and adding two for the highest integer and subtracting 2 for the lowest integer. 2010/3=630, so the numbers are 628, 630 and 632
The integers are 5 and 7.
an integer is a full number 5=integer 1.54= not an integer so 3 examples of adding integers. 1+5+9 = 15 9+4 = 13 15+1+3+2 = 21