The numbers are 51, 52, 53, 54 and 55.
You can find this easily because the average (mean) of the 5 numbers will
be the sum (265) divided by 5. (which is twice the sum divided by 10, 530/10 = 53)
265/5 = 53, which becomes the center number, and the two numbers to either side, 53-2, 53-1, 53+1, 53+2 are the other four.
Another example:
the 5 consecutive numbers that total to 1205 are 239, 240, 241, 242, 243
because 1205/5 = 2410/10 = 241. As long as the sum ends in 5 or zero, it is straightforward.
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No. There is no set of three consecutive even integers with a sum of 40.
There are two consecutive even integers. The numbers are 118 and 120.
191, 192, 193.
The sum is four.
201