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What is the answer to this question find all the 2 digit positive integers n such that the remainder of the division of 2011 by n is 13?
Wiki User
∙ 12y ago
You got
2011%n = 13 (remainder or 2011/n is 13)
or n * x + 13 = 2011 (here x is any natural number)
or n * x = 1998,
All you got to do is find 2 digit factor to 1998 and you're done.
So the answer is : 18, 27, 37, 54, and 74
factors of 1998: 1, 2, 3, 6, 9, 18, 27, 37, 54, 74, 111, 222, 333, 666, 999 and 1998
Wiki User
∙ 12y ago
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