Infinity
They are 14, 16 and 18.
Type your answer here... 3 and 82
let x be the first integer. therefore (x-3)=(36-x)*2. (36-x)*2 expanded=(72-2x) (x-3)=(72-2x). 3x-3=72. 3x=75 x=25. 36-25=11. Answer: the smaller number is 11.
Let's name the first number "X" and the other number "Y" thus: 2X+5Y is the same thing as twice a number more than five times another
Infinity
ok this is what it looks like to me...I definitely could be wrong. one integer is three more than twice another integer if one integer is three more than another number (x+3=y) Then you just multiply "the other number" by 2. (x+3=2*y) Sum of two integers is 36....so add them (x+y=36) Solve that equation for one number so...(y=36-x) Then you would plug that equation into the first equation where there is a y: (x + 3 = 2*(36-x))
??? explain better.
They are 14, 16 and 18.
The smaller integer is 6, the larger integer is 32
The numbers are 14, 16 and 18.
no one wants to know the answer. its freaking math
a = b + 7; 2a = b2 - 1. Substituting: 2b + 14 = b2 - 1 or b2 - 2b - 15 = 0 Factors are (x - 5)(x + 3) b = 5, a = 12. Also works with b = -3 and a = 4
less than
One number is eight more than twice another if their difference is 25. The larger number is 42
Type your answer here... 3 and 82
let x be the first integer. therefore (x-3)=(36-x)*2. (36-x)*2 expanded=(72-2x) (x-3)=(72-2x). 3x-3=72. 3x=75 x=25. 36-25=11. Answer: the smaller number is 11.