x(x2 + 36)
x2-5x-36 = (x-9(x+4) when factored
(x + 4)(x + 9)
4x2+20x+25 (2x+5)^2
x-4 is the correct answer for Apex
x2 + 36 = 20x so x2 - 20x + 36 = 0 so x2 - 2x - 18x + 36 = 0 or x(x - 2) - 18(x - 2) = 0 that is (x - 2)(x - 18) = 0 so x - 2 = 0 or x - 18 = 0 ie x = 2 or x = 18
(x - 10)(x - 10)
4x2 - 20x + 16 = 4(x2 - 5x + 4) = 4(x - 1)(x - 4)
If: y = x2+20x+100 and x2-20x+100 Then: x2+20x+100 = x2-20x+100 So: 40x = 0 => x = 0 When x = 0 then y = 100 Therefore point of intersection: (0, 100)
x2 + 20x - 39 = 0: Add 61 giving: x2 + 20x + 100 = (x + 10)2
Setting to zero may help. 36 - X2 = 0 36 = X2 take square root each side (+/-) 6 = X ========
x2 + 13x + 36 = (x + 9)(x + 4)
When factored it is: (x-9)(x+4)
x(x2 + 36)
-32
x2-5x-36 = (x-9(x+4) when factored
I assume x2 + 5x - 36 is the polynomial in the question. First, look for two factors of 36 that have a difference of 5, which would be 9 and 4. It would factor into (x + 9)(x - 4). To double check, multiplying them together results in x2 - 4x + 9x - 36 = x2 + 5x - 36. If the polynomial is 5x2 +7x +2