There is a formula for "the difference of squares." In this case, the answer is (6x + 11y)(6x - 11y)
-28
66x^3 - 36x^2 = 6x^2(11x - 6) 55x - 30 = 5(11x - 6) 66x^3 - 36x^2 + 55x - 30 = (6x^2 + 5)(11x - 6)
factor I (fibrinogen), factor II (prothrombin), factor III (tissue thromboplastin), factor IV (calcium), factor V (proaccelerin), factor VI (no longer considered active in hemostasis), factor VII (factor-vii), factor VIII (antihemophilicfactor), factor IX (plasma thromboplastincomponent; Christmas factor), factor X (stuart-factor-stuart-prower-factor), factor XI (plasma thromboplastinantecedent), factor XII (factor-xii), factor XIII (fibrin stabilizing factor).
factor pair = 36,1 factor pair = 18,2 factor pair = 12,3 factor pair = 9,4 factor pair = 6,6
(6x+5)(6x-5)
36x2=72
The difference of two squares is quick way to factor polynomials when certain constraints are met: Namely that you have two squares (e.g. 4, 25, 36x2 , 144a6) and one is subtracting from the others (e.g. 25 - 36x2). IF these two constraints are met, then you are able to factor the polynomial by finding the square roots of the squares. sqrt(25)=5 sqrt(36x2) = 6x Therefore 25 - 36x2 = (5+6x)(5-6x) in factored form. In general, given any two squares, a2 and b2, AND they are subtracting, a2 - b2, you can factor them to be (a + b)(a - b).
362+60x+25 (6x+5)(6x+5)
(6x + 5)(6x + 5) or (6x + 5)2
36x2 + 12x + 1 = (6x + 1)2
36x2=72
If that's + 6x3, the answer is x(x - 6)(x + 6)(x + 6) or x(x - 6)(x + 6)2
y = -36x2 - 55x + 14; since -36(14) = 4(-9)(7)(2) = 8(-63) and 8 + (-63) = -55, then y = (-36x2 - 63x) + (8x + 14); factor out -9x and 2 y = -9x(4x + 7) + 2(4x + 7); factor out 4x + 7 y = (4x + 7)(-9x + 2); let y = 0 0 = (4x + 7)(-9x + 2); let each factor equal to zero and solve for x 4x + 7 = 0 or -9x + 2 = 0 x = -7/4 or x = 2/9 Thus, the parabola cuts the x-axis at -7/4 and 2/9.
(6x + 5)(6x - 5)
It can be factored as 18(5-2x^2)
36x2 - 4y2 = (6x - 2y) (6x + 2y)