3x2 + 15x + 6 = 3*(x2 + 5x + 2). There are no further rational factors.
(x-11)(x-4)
x2(x3 + 1) is the best you can do there.
x2 + 7x + 6 = (x + 6) (x + 1)
x2 + 13x + 36 = (x + 9)(x + 4)
You can't factor it
15x2 + 2x - 56 = 15x2 + 30x - 28x - 56 = 15x(x + 2) - 28(x + 2) = (15x - 28)(x + 2)
3x2 + 15x + 6 = 3*(x2 + 5x + 2). There are no further rational factors.
(x-11)(x-4)
(x - 1)(x - 14)
x2+15x+14 = (x+1)(x+14)
x2-15x+56 = 0 (x-8)(x-7) = 0 Therefore: x = 8 or x = 7 To ensure that your answer is correct multiply out the brackets and you should go back to the original quadratic equation.
(x - 4)(x - 11)
(x - 6)(x - 9)
3x3+15x2+18x = 3x(x2+5x+6) = 3x(x+2)(x+3)
This will only give a rational answer when it's +56. Then you're looking for two numbers that add to 15 and multiply to 56. That's 7 and 8. If it's -15x, the answer is (x - 8)(x - 7) If it's +15x, the answer is (x + 8)(x + 7)
The correct classification of x2 15x is a monomial.