x2-15x+56 = 0 (x-8)(x-7) = 0 Therefore: x = 8 or x = 7 To ensure that your answer is correct multiply out the brackets and you should go back to the original quadratic equation.
(x - 3)*(x + 5)*(x - 1) = 0 (x2 - 3x + 5x - 15)*(x - 1) = 0 (x2 + 2x - 15)*(x - 1) = 0 (x3 + 2x2 - 15x - x2 - 2x + 15) = 0 ie x3 + x2 - 17x + 15 = 0
(x-6)(x-9) I did that by factoring 54 until I found two numbers that added up to 15.
3x3+15x2+18x = 3x(x2+5x+6) = 3x(x+2)(x+3)
-9y-15x ---- -3
x2+15x+14 = (x+1)(x+14)
The expression x2 + 3x +8 is a quadratic trinomial.
x2-15x+56 = 0 (x-8)(x-7) = 0 Therefore: x = 8 or x = 7 To ensure that your answer is correct multiply out the brackets and you should go back to the original quadratic equation.
You can't factor it
It is a quadratic polynomial with integer coefficients..
This question does not make sense. If it should be X2 x 15X -54, the answer is: X2 -15X + 54 = (X - 6)(X -9)
It's an equation. If you want to solve it for x, you can do so as follows: x2 + 15x = 30 x2 + 15x + (15/2)2 = 30 + (15/2)2 (x + 15/2)2 = 30 + 225/2 x + 15/2 = ± √(285/2) x = (-15 ± √570) / 2
(x + 7)(x + 8)
3x2 + 15x + 6 = 3*(x2 + 5x + 2). There are no further rational factors.
3x2 - 15x + 42 = 3*(x2 - 5x + 14) which cannot be factorised further.
(x-11)(x-4)
(x - 1)(x - 14)