The correct classification of x2 15x is a monomial.
x2-15x+56 = 0 (x-8)(x-7) = 0 Therefore: x = 8 or x = 7 To ensure that your answer is correct multiply out the brackets and you should go back to the original quadratic equation.
(x - 3)*(x + 5)*(x - 1) = 0 (x2 - 3x + 5x - 15)*(x - 1) = 0 (x2 + 2x - 15)*(x - 1) = 0 (x3 + 2x2 - 15x - x2 - 2x + 15) = 0 ie x3 + x2 - 17x + 15 = 0
(x-6)(x-9) I did that by factoring 54 until I found two numbers that added up to 15.
3x3+15x2+18x = 3x(x2+5x+6) = 3x(x+2)(x+3)
-9y-15x ---- -3
x2+15x+14 = (x+1)(x+14)
The expression x2 + 3x +8 is a quadratic trinomial.
x2-15x+56 = 0 (x-8)(x-7) = 0 Therefore: x = 8 or x = 7 To ensure that your answer is correct multiply out the brackets and you should go back to the original quadratic equation.
You can't factor it
This question does not make sense. If it should be X2 x 15X -54, the answer is: X2 -15X + 54 = (X - 6)(X -9)
It is a quadratic polynomial with integer coefficients..
It's an equation. If you want to solve it for x, you can do so as follows: x2 + 15x = 30 x2 + 15x + (15/2)2 = 30 + (15/2)2 (x + 15/2)2 = 30 + 225/2 x + 15/2 = ± √(285/2) x = (-15 ± √570) / 2
(x + 7)(x + 8)
3x2 - 15x + 42 = 3*(x2 - 5x + 14) which cannot be factorised further.
3x2 + 15x + 6 = 3*(x2 + 5x + 2). There are no further rational factors.
(x-11)(x-4)
(x - 1)(x - 14)