x2 -11x-12= (x-12)(x+1)
It doesn't factor evenly if it were x**2-11x+10: x**2-11x+10 = (x-1)(x-10)
I assume you mean...,X2 + 11X + 10(X + 1)(X + 10)==============factored
x2 + 11x + 24 You want the equation to be in the form (x + a)(x + b), where the two solutions are -a and -b.You know that...ab = 24...and...a + b = 11Note that 8 times 3 is 24, and 8 plus 3 is 11.x2 + 11x + 24 = (x + 3)(x + 8)The two answers are x = -3 and x = -8.
(x + 9)(x + 2)
Assuming the question is written as: x2+11x-12 This would factor to: (x+12)(x-1)
This is the equation we want to factorize: x2 - 11x + 18 And there are two answers (the numbers are the same, but +/- signs are inverted): 1. (x - 2)(x - 9) = x2 - 9x - 2x -(-18) = x2 - 11x + 18 2. (-x + 2)(-x +9) = x2 -9x -2x + 18 = x2 - 11x + 18
x2 - 11x + 24 = (x - 3)(x - 8)
x2 -11x-12= (x-12)(x+1)
It is (x+2)(x+9) when factored
x^3 - 121x
X2 -11x +10=(x - 1 )(x - 10)
The factors of (x2 + 11x + 30) are (X + 5) and (x + 6)You want to look for two numbers, when multiplied equal 30, and when added equal 11. Start with factors of 30, and see what they add to: 5+6=11, and 5*6=30.
21
x^2 + 11x + 6 has no rational zeros.
x(6x - 11)
x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.