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How would you find 3 consecutive integers such that twice the third is 15 more than the first?
Let's denote the first integer as x. The next two consecutive integers would be x+1 and x+2. According to the given condition, twice the third integer (2(x+2)) is equal to 15 more than the first integer (x+15). Setting up the equation: 2(x+2) = x + 15. Solving this equation will give you the first integer, which you can then use to find the consecutive integers.
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The sum of three consecutive even integers is fourteen less than twice the smallest of these integers. What is the smallest and greatest integers?
three consecutives numbers: a = smallest a+2 a+4 14 less = -14 than twice the smallest = 2a so... a+a+2+a+4=-14+2a 3a+6=-14+2a 3a-2a=-14-6 a=-20 answer: smallest = -20 greatest = -16
Two positive integers have a product of 50 one is twice the other what are the integers?
5 and 10
What are the two positive integers that have a product of 98 where one integer is twice the other?
The integers are 14 and 7.
The sum of two integers is 51. The larger integer is 3 more than twice the smaller integer. Find the two integers?
no one wants to know the answer. its freaking math
What five consecutive integers have the sum of 265?
The numbers are 51, 52, 53, 54 and 55. You can find this easily because the average (mean) of the 5 numbers will be the sum (265) divided by 5. (which is twice the sum divided by 10, 530/10 = 53) 265/5 = 53, which becomes the center number, and the two numbers to either side, 53-2, 53-1, 53+1, 53+2 are the other four. Another example: the 5 consecutive numbers that total to 1205 are 239, 240, 241, 242, 243 because 1205/5 = 2410/10 = 241. As long as the sum ends in 5 or zero, it is straightforward.
Find three consecutive even integers such that the sum of the first twice the second and three times the third is 124?
18, 20 and 22
How do you find three consecutive integers so that twice the first increased by three times the third will be -24?
The three integers, since they are consecutive, can be listed as a, a+1, and a+2. Twice the first is 2a. Three times the third is 3(a+2) = 3a+6. First make a formula of the information given: 2a+(3a+6)= -24 Next, solve the formula: 5a + 6 = -24 Subtract 6 from each side. 5a = -30 Divide each side by 5. a = -6 The three consecutive numbers are -6, -5, and -4.
Find three consecutive integers such that the sum of the first twice the second and three times the third is 86?
n + 2(n+1) + 3(n+2) = 86 n + 2n + 2 + 3n + 6 = 86 6n = 86 - 2 - 6 6n = 78 n = 13 Three consecutive integers are = 13,14,15
Find the smallest of four consecutive even integers if twice the sum of the second and third integers is equal to the sum of the first and fourth integers increased by fourteen?
Since we know that the integers are even and consecutive, we can call them x, x+2, x+4, and x+6, with x being the smallest of the four. twice the sum of the second and third can be written as 2(x+2+x+4)=4x+12 the sum of the first and fourth increased by 14 is x+x+6+14=2x+20 Then we can solve 4x+12=2x+20-->2x=8-->x=4 4
Find three consecutive odd integers such that the sum of the first integer twice the second integer and three times the third is 70?
9, 11, and 139 + 2(11) + 3(13) = 9 + 22 + 39 = 70
Three times the first of three consecutive odd integers is three more than the twice and the third What is the average of the three integers?
Let the first of the three odd consecutive integers be x, so that the second of these integers would be x + 2, and the third one would be x + 4. We have: 3x = 2[(x + 2)+ (x + 4)] + 3 3x = 2(2x + 6) +3 3x = 4x + 12 + 3 (subtract 4x to both sides) -x = 15 (multiply by -1 to both sides) x = -15 (the first one) So the integers are -15, -13, and -11. The average of those integers is (-15 + -13 + -11)/2 = -39/2 = -19.5.
Five times the smallest of three consecutive even integers is 10 more than twice the largest. find the integers?
5872345098234783904672083946728390752430689723409687298290843 theres your answer
How Find three consecutive even integers such that three times the first integer i six more than twice the second integer?
They are 14, 16 and 18.
Find two consecutive integers such that the larger is nine more than twice the smaller?
-10 and -11.
What are two consecutive odd integers that when twice the larger is added to the small the result is 169?
55 and 57
How Find three consecutive even integers such that three times the first integer is six more than twice the second integer?
The numbers are 14, 16 and 18.
Find two consecutive odd integers if twice the larger increased by the smaller equals 85?
27, 29
