0

# What is the the correct trigonometric ratio of sin?

Updated: 4/28/2022

Wiki User

10y ago

There is not a "correct" trigonometric ratio. The one based on right angled triangles are limited to right angled triangles and so cannot be used for angles greater than pi radians (180 degrees). This is despite the fact that the sine ratio is defined for any angle, including reflex angles or angles of negative measure.

To find the sine of an angle of measure q, draw a line that makes that angle with the positive direction of the x-axis, the angle being measured in the anti-clockwise direction. If (x, y) are the coordinates of any point on that line, then

sin(q) = x/sqrt(x2 + y2)

There is not a "correct" trigonometric ratio. The one based on right angled triangles are limited to right angled triangles and so cannot be used for angles greater than pi radians (180 degrees). This is despite the fact that the sine ratio is defined for any angle, including reflex angles or angles of negative measure.

To find the sine of an angle of measure q, draw a line that makes that angle with the positive direction of the x-axis, the angle being measured in the anti-clockwise direction. If (x, y) are the coordinates of any point on that line, then

sin(q) = x/sqrt(x2 + y2)

There is not a "correct" trigonometric ratio. The one based on right angled triangles are limited to right angled triangles and so cannot be used for angles greater than pi radians (180 degrees). This is despite the fact that the sine ratio is defined for any angle, including reflex angles or angles of negative measure.

To find the sine of an angle of measure q, draw a line that makes that angle with the positive direction of the x-axis, the angle being measured in the anti-clockwise direction. If (x, y) are the coordinates of any point on that line, then

sin(q) = x/sqrt(x2 + y2)

There is not a "correct" trigonometric ratio. The one based on right angled triangles are limited to right angled triangles and so cannot be used for angles greater than pi radians (180 degrees). This is despite the fact that the sine ratio is defined for any angle, including reflex angles or angles of negative measure.

To find the sine of an angle of measure q, draw a line that makes that angle with the positive direction of the x-axis, the angle being measured in the anti-clockwise direction. If (x, y) are the coordinates of any point on that line, then

sin(q) = x/sqrt(x2 + y2)

Wiki User

10y ago

Wiki User

10y ago

There is not a "correct" trigonometric ratio. The one based on right angled triangles are limited to right angled triangles and so cannot be used for angles greater than pi radians (180 degrees). This is despite the fact that the sine ratio is defined for any angle, including reflex angles or angles of negative measure.

To find the sine of an angle of measure q, draw a line that makes that angle with the positive direction of the x-axis, the angle being measured in the anti-clockwise direction. If (x, y) are the coordinates of any point on that line, then

sin(q) = x/sqrt(x2 + y2)