The nth triangular number is given by ½ × n × (n+1)
→ the 5857th triangular number is ½ × 5857 × 5858 = 17,155,153, so its units digit is a 3.
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Alternatively,
If you look at the units digits of the first 20 triangular numbers they are {1, 3, 6, 0, 5, 1, 8, 6, 5, 5, 6, 8, 1, 5, 0, 6, 3, 1, 0, 0}
At this stage, as we are only concerned with the units digit, as we now have a 0 for the units digit, when 21 is added it is the same as adding 1 to 0 to give a 1, for the 22nd triangular number, we are adding 2 to the 1 to give 3, and so on - the sequence of 20 digits is repeating.
To find the units digit of the nth triangular number, find the remainder of n divided by 20 and its units digit will be that digit in the sequence (if the remainder is 0, use the 20th number). To find the remainder when divided by 20 is very simple by looking at only the tens digit and the units digit:
5857 ÷ 20 = ... remainder 17; the 17th digit of the above sequence is a 3, so the units digit of the 5857th triangular number is a 3.
This trick can be used for much larger triangular numbers which calculators cannot calculate exactly using the above formula. eg the units digit of the 1234567890123456789th triangular number is... 1234567890123456789 ÷ 20 = .... remainder 9, so this triangular number's units digit is the 9th digit of the above sequence which is a 5.
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Any two digit number in which: (a) the units digit is not 0, and (b) the two digits are different will form a new 2-digit number when the digits are interchanged.
the largest 6 digit number is 999999 however following the rules provided, the largest number would be 789643.
4 is in the tens place of the number 43. The 3 is in hte ones place.
In the number 63, the value of the digit 3 is 3 units. Each digit in a multi-digit number holds a place value based on its position. In this case, the 3 is in the units place, so its value is simply 3. The 6 in 63, on the other hand, represents 6 tens.