0
so say y = 2^x
dy/dx = ln2.2^x
(. = multiplication symbol, ^ = to-the-power-of symbol)
The general formula is
(where 'a' is a constant, x is what you are differentiating with respect to and y is f(x))
y = a^x
then
dy/dx = lna.a^x
Go ask a math teacher or look up exponential function differentiation on the internet for why.
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