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How do you find the domain and range of the function f of x equals half of the absolute value of x minus 2?
The domain could be the real numbers, in which case, the range would be the non-negative real numbers.
How do you determine what the domain and range of a function are?
The domain of a function pertains to all the x values The range of a function pertains to all the y values So domain and range do not get confused, this can be easily remembered by the order of the how the first letter of the word appears in the English alphabet. d, domain, goes before r, range x goes before y domain = x values range = y values ill try to add to the previous writer. previously, he wrote what the domain and range are for easier functions, but not how to determine them. more generally, what the domain is, is what you can put into a function, which in simpler cases, is jus x. to find what you can put in, it helps to find what you cant put in for x, meaning, where is the graph of the function discontinuous. for example, if we look at the function f(x)=1/(1-x) if we put 1 in for x, then the denominator goes to zero and the function is discontinuous at that x value, therefore 1 will not be included in the domain, but everything else will be included since there are no other disconinuities. the domain will end up looking like this- (-infinity,1), (1,infinity). now for the range, all you have to do is find what you can get out of the function from what you can put in, which can usually be done by putting the values you see for the domain in. putting negative infinity in for x in f(x)=1/(1-x) you get zero and putting one in you get infinty. putting it together you get (-infinity,0), (0,infinity) for your range. p.s. as i stated before, more generally, your domain is more so what you put into your function, so it is not always x, for example, in the case of a function of 2 variables such as f(x,y), what you can put in for both x and y will make up your domain, not just x, and y will most certainly not be your range, rather it will be the values of f(x,y).
How do you find the domain and range of f of x equals x squared minus 3x minus 10?
The domain is what you choose it to be. You could, for example, choose the domain to be [3, 6.5] If the domain is the real numbers, the range is [-12.25, ∞).
What is the domain of the function f x x 2 plus 4?
The domain of the function f (x) = square root of (x - 2) plus 4 is Domain [2, ∞)
What is the relationship between the domains and ranges of a function and its inverse?
The domain of a function, f(x), is a set of real numbers (call them values of x) which corresponds to a second set, called the range, such that each element in the domain corresponds to exactly one element in the range ( y- value). So the range is the set of real numbers that are values of the function. An inverse of a function f(x) is denoted by f-1(x) where -1 is NOT an exponent. The notation f-1 does not mean 1/f (so it looks like a neg 1 exponent but it is not. Math people know to read this as the inverse function). Any function that passes the horizontal line test (which intersects the graph of the function only once) has an inverse, also it is a one-to-one function. Any one-to-one function has a graph that passes the horizontal line test. A one-to one function is a function in which not two different pairs have the same second component. For this kind of functions (one-to-one functions), the domain becomes the range for the inverse and vv. It means that if a point (x, y) is on the graph of f, then the point (y, x) is on the graph of f-1. Ex: y or f(x) = x2 (the domain is the set of all real numbers. you can square positives, negatives, fractions etc. the range is only all reals greater than or equal to zero). The graph of f(x) = x2 does not pass the horizontal test, because it intersects the graph at two points, let's say (-3, 9) and (3, 9). Inverse functions have ordered pairs with the coordinates reversed. If we interchange x- and y-coordinates then we obtain (9, -3) and (9, 3) but these ordered pairs do not define a function. Thus this function does not have an inverse. But if we restrict the domain, for example the set of all positive numbers including zero, then we allow it to have one, and this inverse function f-1 is a reflection of the graph of f about the line y = x, where f(x) = x2 and its domain is {x| x ≥ 0}. The inverse of the above function is the square root of x. which I will abbreviate as sq rt the inverse function becomes f-1(x) = √x (in other words, f you limit yourself to real numbers, you cannot use any negatives in place of x for this inverse function. So the domain of the inverse is all reals > or = 0. If the inverse is to be a function you cannot have any answers which are negative. the relation would not pass the vertical line test. so the range is also only reals > or = zero).
How do you determine the range of f?
I assume the question is about the range of a function f. First, determine the domain of the function f. This is the set of all inputs. Use this information to find all the output values of f: that is the range. In most cases, you will not have to evaluate f for each and every input: the nature of f will help you.
What is the range of F(x)dividing x?
The range of F(x)dividing x depends on the domain of x and on the function F.
What is the domain and range for the following function and its inverse f of x equals -x plus 5?
The function is a simple linear function and so its nature does not limit the domain or range in any way. So the domain and range can be the whole of the real numbers. If the domain is a proper subset of that then the range must be defined accordingly. Similarly, if the range is known then the appropriate domain needs to be defined.
What is the example of the range and domain in a function?
A function is a mapping from one set to another. It may be many-to-one or one-to-one. The first of these sets is the domain and the second set is the range. Thus, for each value x in the domain, the function allocates the value f(x) which is a value in the range. For example, if the function is f(x) = x^2 and the domain is the integers in the interval [-2, 2], then the range is the set [0, 1, 4].
How do you find the domain and range of the function f of x equals half of the absolute value of x minus 2?
The domain could be the real numbers, in which case, the range would be the non-negative real numbers.
What is meant by the term domain and range in maths?
Quite simply, the domain is the input and the range is the output of a function. If your using a typical X-Y axis graph, it may be useful to view the X axis as where the domain lies. The Y axis is where the range lies. Y= f(x) or Range = f(domain)
What is pass marks of intermediate first year maths 1a for mec?
find the domain and range of the function f(x)=x/2-3x
What is the range of the function f(x)12-3x for the domain -4-2024?
It is 24, 72, -60.
Is the x or the y the domain in a function?
x is a letter often used as a variable. It can be in the range or the domain. However, in elementary algebra, the variable x is most often used for the domain and f(x) =y for the range.
What is meant by f of g of x Specifically address the domain and range?
You would have been given a function for f(x) and another function for g(x). When you want to find f(g(x)), you put the function for g(x) wherever x occurs in f(x). Example: f(x)=3x+2 g(x)=x^2 f(g(x))=3(x^2)+2 I'm not sure what you mean by address domain and range. They depend on what functions you're given.
How do you determine what the domain and range of a function are?
The domain of a function pertains to all the x values The range of a function pertains to all the y values So domain and range do not get confused, this can be easily remembered by the order of the how the first letter of the word appears in the English alphabet. d, domain, goes before r, range x goes before y domain = x values range = y values ill try to add to the previous writer. previously, he wrote what the domain and range are for easier functions, but not how to determine them. more generally, what the domain is, is what you can put into a function, which in simpler cases, is jus x. to find what you can put in, it helps to find what you cant put in for x, meaning, where is the graph of the function discontinuous. for example, if we look at the function f(x)=1/(1-x) if we put 1 in for x, then the denominator goes to zero and the function is discontinuous at that x value, therefore 1 will not be included in the domain, but everything else will be included since there are no other disconinuities. the domain will end up looking like this- (-infinity,1), (1,infinity). now for the range, all you have to do is find what you can get out of the function from what you can put in, which can usually be done by putting the values you see for the domain in. putting negative infinity in for x in f(x)=1/(1-x) you get zero and putting one in you get infinty. putting it together you get (-infinity,0), (0,infinity) for your range. p.s. as i stated before, more generally, your domain is more so what you put into your function, so it is not always x, for example, in the case of a function of 2 variables such as f(x,y), what you can put in for both x and y will make up your domain, not just x, and y will most certainly not be your range, rather it will be the values of f(x,y).
How do you find the domain and range given a quadratic function?
A quadratic function: f(x) = ax2 + bx + c = 0, where a ≠ 0. Domain: {x| x is a real number}, or in the interval notation, (-∞, ∞). Range: If a > 0, {y| y ≥ f(-b/2a), the y-coordinate of the vertex} or [f(-b/2a), ∞). If a < 0, {y| y ≤ f(-b/2a), the y-coordinate of the vertex} or (-∞, f(-b/2a)]. * * * * * Alternative answer: The domain is anything you chose it to be. For example, the integers between 2.5 and 4.7 (ie 3 and 4) and the real numbers between 4.8 and 5.0. Then the range would be the values of f(x) which corresponded to the values of x in the domain.
