The function ( f(x) = x^2 + 1 ) is a quadratic function. The domain is all real numbers, expressed as ( (-\infty, \infty) ), since you can input any real number for ( x ). The range is ( [1, \infty) ) because the minimum value of the function occurs at ( x = 0 ), where ( f(0) = 1 ), and the function increases without bound as ( x ) moves away from zero.
sin(x)-cos(x) = (1)sin(x)+(-1)cos(x) so the range is sqrt((1)^2+(-1)^2)=1 and the domain is R <><><><><> The domain of sin x - cos x is [-infinity, +infinity]. The range of sin x - cos x is [-1.414, +1.414].
if y = x2 + 1 Then the minimum value of y is 1, which happens at the point (0, 1). It lies in the domain of real numbers. i.e. {y | y ≥ 1, y ∈ ℝ}
To find the domain of the function ( f(x) = x^2 + 1 ), we identify the set of all possible input values for ( x ). Since this is a polynomial function, the domain is all real numbers, expressed as ( (-\infty, \infty) ). The range is determined by analyzing the output values; the minimum value of ( f(x) ) occurs at ( x = 0 ), giving ( f(0) = 1 ). Therefore, the range is ( [1, \infty) ).
The domain of the sine function, ( \sin(x) ), is all real numbers, represented as ( (-\infty, \infty) ). The range of the sine function is limited to values between -1 and 1, inclusive, which is expressed as ( [-1, 1] ).
The domain of y = 1/x2 is all numbers from -infinity to + infinity except zero. The range is all positive numbers from zero to +infinity, except +infinity.
the domain is all real numbers the range is from -1 to +1
The answer depends on the domain. If the domain is the whole of the real numbers, the range in y ≥ 1. However, you can choose to have the domain as [1, 2] in which case the range will be [2, 5]. If you choose another domain you will get another range.
The domain of the function 1/2x is {0, 2, 4}. What is the range of the function?
The doman can extend from negative infinioty to positive infinity. Its range is from (+)1 to (-)1.
sin(x)-cos(x) = (1)sin(x)+(-1)cos(x) so the range is sqrt((1)^2+(-1)^2)=1 and the domain is R <><><><><> The domain of sin x - cos x is [-infinity, +infinity]. The range of sin x - cos x is [-1.414, +1.414].
The range of -sin x depends on the domain of x. If the domain of x is unrestricted then the range of y is [-1, 1].
The range is {-7, 1, 9, 17}.
if y = x2 + 1 Then the minimum value of y is 1, which happens at the point (0, 1). It lies in the domain of real numbers. i.e. {y | y ≥ 1, y ∈ ℝ}
To find the domain of the function ( f(x) = x^2 + 1 ), we identify the set of all possible input values for ( x ). Since this is a polynomial function, the domain is all real numbers, expressed as ( (-\infty, \infty) ). The range is determined by analyzing the output values; the minimum value of ( f(x) ) occurs at ( x = 0 ), giving ( f(0) = 1 ). Therefore, the range is ( [1, \infty) ).
Any answers?
what is the domain of g(x) equals square root of x plus 1? √(x+1) ≥ 0 x+1≥0 x≥-1 Domain: [-1,∞)
The domain and the range depends on the context. For example, the domain and the range can be the whole of the complex field. Or I could define the domain as {-2, 1, 5} and then the range would be {0, 3, -21}. When either one of the range and domain is defined, the other is implied.