sin(x)-cos(x) = (1)sin(x)+(-1)cos(x) so the range is sqrt((1)^2+(-1)^2)=1 and the domain is R <><><><><> The domain of sin x - cos x is [-infinity, +infinity]. The range of sin x - cos x is [-1.414, +1.414].
if y = x2 + 1 Then the minimum value of y is 1, which happens at the point (0, 1). It lies in the domain of real numbers. i.e. {y | y ≥ 1, y ∈ ℝ}
The domain of y = 1/x2 is all numbers from -infinity to + infinity except zero. The range is all positive numbers from zero to +infinity, except +infinity.
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The range of cosine is [-1, 1] which is, therefore, the domain of cos-1. As a result, cos-1(2) is not defined.
the domain is all real numbers the range is from -1 to +1
The answer depends on the domain. If the domain is the whole of the real numbers, the range in y ≥ 1. However, you can choose to have the domain as [1, 2] in which case the range will be [2, 5]. If you choose another domain you will get another range.
The range of -sin x depends on the domain of x. If the domain of x is unrestricted then the range of y is [-1, 1].
The range is {-7, 1, 9, 17}.
what is the domain of g(x) equals square root of x plus 1? √(x+1) ≥ 0 x+1≥0 x≥-1 Domain: [-1,∞)
The domain and the range depends on the context. For example, the domain and the range can be the whole of the complex field. Or I could define the domain as {-2, 1, 5} and then the range would be {0, 3, -21}. When either one of the range and domain is defined, the other is implied.
It is because that is how "plus" is normally defined. But 1 plus 1 need not be two. It all depends on the domain and range that you are working with and what you mean by the binary operation "plus". If 1 means make an about turn, and "plus" means "follow it with", then 1 plus 1 is "make an about turn" and then "make an about turn". If you do that you are back where you started. So in this case, 1 plus 1 is the same as zero.
The range could be anything. Without parameters specified, the domain of {1,2,3,4} could have any range. This problem is unsolvable.
Assuming a large enough domain, the range is -1 to 1.
The domain (input) is all possible angles. The range (output) is -1 to +1.
Let the function be f(x) = 1/(x-1) The domain is all allowable values for which the function can be defined. Here, except 1, any number would give the function a meaningful value. If x=1, the denominator becomes 0 and the function becomes undefined. Therefore, the domain is all real numbers except 1. The range is all values assumed by the function. Here, the range is negative infinity to plus infinity (that is , all real numbers).
The domain of a function, is the range of input values which will give you a real answer.For example the domain of x+1 would be all real numbers as any number plus 1 will be another real numberThe domain of x0.5 would be all positive numbers as the answer to square root of a negative number is not realNote:x0.5 means the square root of x* * * * *Not quite. A function is a one-to-one or many-to-one mapping from a set S to a set T (which need not be a different set). A function can be one whose domain is all the cars parked in a street and the range is the second character of their registration number.A mathematical function can have the complex field as its domain and range, so a real answer is not a necessary requirement for a function.