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What are the solutions to the simultaneous equations of x squared plus xy plus y squared equals 7 and 2x plus y equals 1 showing work?
To solve the system of equations x^2 + xy + y^2 = 7 and 2x + y = 1, we can first solve the second equation for y to get y = 1 - 2x. Substituting this into the first equation yields x^2 + x(1-2x) + (1-2x)^2 = 7. Simplifying this equation gives a quadratic equation in terms of x, which can be solved to find two possible values for x. Substituting these values back into the equation y = 1 - 2x will give the corresponding values for y.
What else can I help you with?
What is x y squared?
You can only get a specific number for an expression if you assign numbers to the variables. As an expression, the existing expression cannot be simplified.
Which equation has a solution of -4?
There are an infinite number of equations with this solution, eg x = 6 - 10; x = 45678 - 45682; x squared = 16 etc etc
X squared minus 5x minus 24?
The equation x2 - 5x - 24 = 0 has the two solutions 8 and -3 for x.
What are the solutions to the simultaneous equations of 3xy -y squared equals 8 and x -2y equals 1?
The two equations are: 1) 3xy - y² = 8 2) x - 2y = 1 Make x the subject of (2): x - 2y = 1 → x = 2y + 1 substitute for x in (1) and solve for y: 3xy - y² = 8 → 3(2y + 1)y - y² = 8 → 6y + 3y - y² - 8 = 0 → 5y + 3y - 8 = 0 → (5y + 8)(y - 1) = 0 → 5y + 8 = 0 → y = -8/5 or y - 1 = 0 → y = 1 and substitute into 2 to find the corresponding x: y = -8/5 → x = 2(-8/5) + 1 = -11/5 y = 1 → x = 2(1) + 1 = 3 → the solutions are the ordered pairs (-11/5, -8/5) {or (-2.2, -1.6)} and (3, 1)
How do you foil 2x squared plus 7x plus 5?
This is a quadratic equation, and so you it falls under the rule: ax squared + bx + c. This means you need to times the 2x squared by 5, which is 10. Then you need to find the factors of ten, i.e. 2 and 5, 10 and 1. You need to find the pair of factors that add to make 7x, which would be 2 and 5. you then need to put these into the equation - it would become 2x squared + 2x (as one equation) and 5x + 5 would be another equation. we can see that 2x squared and 2x have 2x in common, and so the answer for that would be 2x (x + 1). the second equation would be 5 (x + 1). the two equations have x + 1 in common, and that would make up the first set of brackets. you then add the rest (2x +5) and your answer would be (x+1) (2x+5). FOIL is a different method used for 'easier' equations - less complicated. :)
What are the solutions to the simultaneous equations of x squared plus y squared equals 20 and 2y minus x equals 0?
The solutions are: x = 4, y = 2 and x = -4, y = -2
What are the solutions to the simultaneous equations of x -2y equals 1 and 3xy -y squared equals 8?
They are: (3, 1) and (-11/5, -8/5)
What are the solutions to the simultaneous equations of 2x plus y equals 5 and x squared -y squared equals 3?
If: 2x+y = 5 and x2-y2 = 3 Then the solutions work out as: (2, 1) and ( 14/3, -13/3)
What are the solutions of the simultaneous equations of x squared -xy -y squared equals -11 and 2x plus y equals 1?
1st equation: x^2 -xy -y squared = -11 2nd equation: 2x+y = 1 Combining the the two equations together gives: -x^2 +3x +10 = 0 Solving the above quadratic equation: x = 5 or x = -2 Solutions by substitution: (5, -9) and (-2, 5)
What are the solutions to -x squared plus 2x plus 4 and x-2?
These are two expressions, not equations. Expressions do not have solutions, only equations do. NB equations include the equals sign.
What are 3 real rational solutions to this system of equations z equals x squared y equals z squared x equals y squared?
The two rational solutions are (0,0,0) and (1,1,1). There are no other real solutions.
How many solutions can two unique equations that both have two squared variables?
Four.
Up to how many solutions can there be in a system of two unique equations that both have two squared variables?
4
What are the solutions to the simultaneous equations of 2x plus y equals 5 and x squared minus y squared equals 3?
Merge the equations together and form a quadratic equation in terms of x:- 3x2-20x+28 = 0 (3x-14)(x-2) = 0 x = 14/3 or x = 2 So when x = 14/3 then y = -13/3 and when x = 2 then y = 1
What are the solutions to the simultaneous equations of x equals 2y -2 and x squared equals y squared plus 7 showing work and answers?
If: x = 2y-2 and x^2 = y^2+7 Then: (2y-2)^2 = y^2+7 So: (2y-2)(2y-2) = y^2+7 It follows: 4y^2-y^2-8y+4-7 = 0 => 3y^2-8y-3 = 0 Solving the above quadratic equation: y = -1/3 or y = 3 Solutions: when y = 3 then x = 4 and when y = -1/3 then x = -8/3
What is another name for solution in equations using x squared 2x plus 1 0?
If you mean: x2+2x+1 = 0 then it is a quadratiic equations whose solutions are equal because x = -1 and x = -1
What are the solutions to the simultaneous equations of x equals 2y -2 and x squared equals y squared plus 7 showing work?
If: x = 2y-2 and x^2 = y^2+7 Then: (2y-2)^2 = y^2+7 => 4y^2-8y+4 = y^2+7 => 3y^2-8y-3= 0 Solving the above quadratic equation: y = -1/3 or y = 3 Solutions by substitution: when y=-1/3 then x=-8/3 and when y=3 then x=4
