X + 4 is a factor of x^3 + 3x^2 - 10x - 24 along with (x + 2) and (x - 3)
x2 - 10x - 24= x2 - 12x + 2x - 24= x(x - 12) + 2(x - 12)= (x - 12)(x + 2)
The equation x2 - 5x - 24 = 0 has the two solutions 8 and -3 for x.
x3 + 6x2 - 4x - 24 = (x + 6)(x2 - 4) = (x + 6)(x + 2)(x - 2)
2z+6z+24=0 8z+24=0 8z= -24 z= - 3
x2+10x-24 = (x-2)(x+12)
-8x+24 {This answer may be wrong: I think the question was intended to read, "Factor x2 - 10x + 24?" If so, the factors are (x - 6) and (x - 4)}
x2-10x-24 = (x+2)(x-12) when factored
X + 4 is a factor of x^3 + 3x^2 - 10x - 24 along with (x + 2) and (x - 3)
2x+8x-2=22 10x-2=22 10x+2=+2 10x=24 10/10=24/10 x=2.4
7x+6 = -3x-24 7x+3x = -24-6 10x = -30 x = -3
Though 10x +24 is an expression and it can not be evaluate, we can write 10x+24=2 • (5x + 12)
Though 10x +24 is an expression and it can not be evaluate, we can write 10x+24=2 • (5x + 12)
3x2 + 10x - 8The auxiliary equation is 3x2 + 10x - 24 [because 8*3 = 24] Two factors of -24 which sum to 10 are 12 and -2. So the factorisation of the auxillary is (3x + 12)*(3x - 2) = 3*(x + 4)*(3x - 2) Dividing by the 3 used to create the auxiliary gives the solution as (x + 4)*(3x - 2).
x2+10x-24 = (x-2)(x+12) when factored
(x + 2)(x - 12)
x^2 - 10x + 24 You're looking for two factors of 24 that equal 10 (x - 6)(x - 4)