x2 - 10x - 24
= x2 - 12x + 2x - 24
= x(x - 12) + 2(x - 12)
= (x - 12)(x + 2)
Twenty-Five x2 + 10x = 8 x2 + 10x + 25 = 8 + 25 (x + 5)2 = 33
x2 + y2 - 10x + 4y - 52 = 0 x2 - 10x + y2 + 4y = 52 Complete the square (x2 - 10x + 25) + (y2 + 4y + 4) = 52 + 25 + 4 (x - 5)2 + (y + 2)2 = 81 (x - 5)2 + (y - -2)2 = 92 This is the equation of a circle with center (5, -2), and radius 9.
x2+10x-33.33 = 0 Using the quadratic equation formula will give you two solutions which are: x = -12.63740794 to 8 decimal places. or: x = 2.63740794 to 8 decimal places
X + 4 is a factor of x^3 + 3x^2 - 10x - 24 along with (x + 2) and (x - 3)
x^(2) - 10x + 24 Since the coefficient of 'x^(2)' is '1', ; number not shownl we look at the constant '24'. Write down all the factors of '24'. They are 1,2,3,4,6,8,12,& 24. From this list we need to select two numbers that add to '10' and multiply to '24'. The possibilities of addition ARE 4 + 6, 2+ 8 , & 12 -2. However, only 4 + 6 = 10 & -4 x -6 = 24 , but -12 X 2 = -24 (Not +24). So the only pair are '4' & '6'. Set up factor brackets;) (x 4)(x 6) Since ;24; is positive (+) then the signs in the brackets are both the same. They can be either '+' or '-' . Since the coefficient of 'x' is '-10' , then the signs are negative(-). So fully factored it is ( x - 4)(x - 6)
x2+10x-24 = (x-2)(x+12) when factored
x2+10x-24 = (x-2)(x+12)
-8x+24 {This answer may be wrong: I think the question was intended to read, "Factor x2 - 10x + 24?" If so, the factors are (x - 6) and (x - 4)}
x2-10x-24 = (x+2)(x-12) when factored
(x + 2)(x - 12)
x^2 - 10x + 24 You're looking for two factors of 24 that equal 10 (x - 6)(x - 4)
Given: x2 + 10x - 16 Let: x2 + 10x - 16 = 0 x2 + 10x - 16 = 0 ∴ x2 + 10x + 25 = 16 + 25 ∴ (x + 5)2 = 41 ∴ x = -5 ± √41 ∴ x2 + 10x - 16 = (x + 5 + √41)(x + 5 - √41)
x2+10x-336
The LCM is x^3 - 100x
For a start you tell us what the expression equals....
(x + 2)(x - 12)
x2 + 10x + 25 --> (x + 5)2