Twenty-Five x2 + 10x = 8 x2 + 10x + 25 = 8 + 25 (x + 5)2 = 33
what two numbers multiply to 24 and add to -10? -4 and -6 look good, so: (x - 4)(x - 6) x = 4 or 6
x2 + y2 - 10x + 4y - 52 = 0 x2 - 10x + y2 + 4y = 52 Complete the square (x2 - 10x + 25) + (y2 + 4y + 4) = 52 + 25 + 4 (x - 5)2 + (y + 2)2 = 81 (x - 5)2 + (y - -2)2 = 92 This is the equation of a circle with center (5, -2), and radius 9.
x2+10x-33.33 = 0 Using the quadratic equation formula will give you two solutions which are: x = -12.63740794 to 8 decimal places. or: x = 2.63740794 to 8 decimal places
X + 4 is a factor of x^3 + 3x^2 - 10x - 24 along with (x + 2) and (x - 3)
x2+10x-24 = (x-2)(x+12) when factored
x2+10x-24 = (x-2)(x+12)
-8x+24 {This answer may be wrong: I think the question was intended to read, "Factor x2 - 10x + 24?" If so, the factors are (x - 6) and (x - 4)}
x2-10x-24 = (x+2)(x-12) when factored
(x + 2)(x - 12)
x^2 - 10x + 24 You're looking for two factors of 24 that equal 10 (x - 6)(x - 4)
Given: x2 + 10x - 16 Let: x2 + 10x - 16 = 0 x2 + 10x - 16 = 0 ∴ x2 + 10x + 25 = 16 + 25 ∴ (x + 5)2 = 41 ∴ x = -5 ± √41 ∴ x2 + 10x - 16 = (x + 5 + √41)(x + 5 - √41)
(x + 2)(x - 12)
For a start you tell us what the expression equals....
The LCM is x^3 - 100x
x2+10x-336
x2 + 10x + 25 --> (x + 5)2