x^(2) - 10x + 24
Since the coefficient of 'x^(2)' is '1', ; number not shownl we look at the constant '24'.
Write down all the factors of '24'. They are 1,2,3,4,6,8,12,& 24.
From this list we need to select two numbers that add to '10' and multiply to '24'.
The possibilities of addition ARE 4 + 6, 2+ 8 , & 12 -2.
However, only 4 + 6 = 10 & -4 x -6 = 24 , but -12 X 2 = -24 (Not +24).
So the only pair are '4' & '6'.
Set up factor brackets;)
(x 4)(x 6)
Since ;24; is positive (+) then the signs in the brackets are both the same. They can be either '+' or '-' .
Since the coefficient of 'x' is '-10' , then the signs are negative(-).
So fully factored it is
( x - 4)(x - 6)
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what two numbers multiply to 24 and add to -10? -4 and -6 look good, so:
(x - 4)(x - 6)
x = 4 or 6
X + 4 is a factor of x^3 + 3x^2 - 10x - 24 along with (x + 2) and (x - 3)
x2 - 10x - 24= x2 - 12x + 2x - 24= x(x - 12) + 2(x - 12)= (x - 12)(x + 2)
The equation x2 - 5x - 24 = 0 has the two solutions 8 and -3 for x.
x3 + 6x2 - 4x - 24 = (x + 6)(x2 - 4) = (x + 6)(x + 2)(x - 2)
2z+6z+24=0 8z+24=0 8z= -24 z= - 3