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If f(x) cos(2x).cos(4x).cos(6x).cos(8x).cos(10x) then find the limit of 1 - f(x)35(sinx)2 as x tends to 0 (zero).?
I'm sorry the question is not correctly displayed. If f(x) = cos(2x).cos(4x).cos(6x).cos(8x).cos(10x) then, find the limit of {1 - [f(x)]^3}/[5(sinx)^2] as x tends to 0 (zero).
Find the measure of this angles m1 equals 123 m8 equals?
Find the measure of this angles m1 equals 123 m8 equals?
What is Cos 2 x divided by cos x?
cos 2x = cos2 x - sin2 x = 2 cos2 x - 1; whence, cos 2x / cos x = 2 cos x - (1 / cos x) = 2 cos x - sec x.
What is sec x cos x?
sec x = 1/cos x sec x cos x = [1/cos x] [cos x] = 1
Find the derivatives of y equals 2 sin 3x?
y=2 sin(3x) dy/dx = 2 cos(3x) (3) dy/dx = 6 cos(3x)
Find all angles in the interval 0 360 satisfying the equation cos theta equals 0.7902?
cos(theta) = 0.7902 arcos(0.7902) = theta = 38 degrees you find complimentary angles
Value of Cos 2 Cos inverse 0.8?
If the angles are measured in radians then the answer is -0.2678
Do all angles have reference angles?
yes
Can you find the reference angle of a quadrantal angle?
Yes. Quadrantal angles have reference angles of either 0 degrees (e.g. 0 degrees and 180 degrees) or 90 degrees (e.g. 90 degrees and 270 degrees).
Why does sin plus cos equal one?
There is no reason at all. For most angles sin plus cos do not equal one.
What are the 3 angles?
sin cos tan -soh cah toa
How to determine the angle of a triangle if you know the length of its sides?
If you know the length of the sides of a triangle you can find all the angles of the triangle using the Law of cosines such as: Step 1. cos A = (b^2 + c^2 - a^2)/(2bc) cos B = (a^2 + c^2 - b^2)/(2ac) cos C = (a^2 + b^2 - c^2)/(2ab) Step 2. Find the arc cosine A, arc cosine B, and arc cosine C in order to find the angles A, B, and C.
What is the relationship between the cos and sin of the non 90 degree angles in a right angle triangle?
sin θ = cos (90° - θ) cos θ = sin (90° - θ)
What is the relationship between sine and cosine of the complementary angles?
sin(x) = cos(90° - x) cos(x) = sin(90° - x)
Cos 195 degree use the trigonometry functions of quadrantal angles and special to find the exact value?
cos(195) = cos(180 + 15) = cos(180)*cos(15) - sin(180)*sin(15) = -1*cos(15) - 0*sim(15) = -cos(15) = -cos(60 - 45) = -[cos(60)*cos(45) + sin(60)*sin(45)] = -(1/2)*sqrt(2)/2 - sqrt(3)/2*sqrt(2)/2 = - 1/4*sqrt(2)*(1 + sqrt3) or -1/4*[sqrt(2) + sqrt(6)]
What is the relationship between the acute angles of a right triangle?
There are many. For example, if A and B are the two acute angles, then A + B = 90 degrees or sin(A) = cos(B) or cos(A) = sin(B) or tan(A) = 1/tan(B)
How do you work this out sin 2x sin x equals cos x?
I would start by looking up the formulae for multiple angles, and convert that to simgle angles. In this case, sin 2x = 2 sin x cos x, so your equation becomes:2 sin x cos x sin x = cos x2 sin2x cos x = cos xNext divide both sides by cos x; note that you must consider the possibility that cos x = 0 (this may give additional solutions to the equation).
