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y = sec(x)*cot(x)*cos(x)
To solve this trigonometric equation, you need to know these identities:
sec(x) = 1/(cos(x))
cot(x) = 1/(tan(x)) = (cos(x))/(sin(x))
Now substitute these identities into the original equation:
y = (1/cos(x))*((cos(x))/(sin(x)))*cos(x)
Now cancel out the terms that are similar in the numerator and denominator to leave you with:
y = (1/(sin(x)))*cos(x)
y = (cos(x))/(sin(x))
From the aforementioned known identity, the final simplified trigonometric equation becomes:
y = cot(x)
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How do you simplify sec x cot x?
sec(x)*cot(x) = (1/cos(x))*(cos(x)/sin(x)) = (1/sin(x)) = csc(x)
Solution for tan x plus cot x divided by sec x csc x?
(tan x + cot x)/sec x . csc x The key to solve this question is to turn tan x, cot x, sec x, csc x into the simpler form. Remember that tan x = sin x / cos x, cot x = 1/tan x, sec x = 1/cos x, csc x = 1/sin x The solution is: [(sin x / cos x)+(cos x / sin x)] / (1/cos x . 1/sin x) [(sin x . sin x + cos x . cos x) / (sin x . cos x)] (1/sin x cos x) [(sin x . sin x + cos x . cos x) / (sin x . cos x)] (sin x . cos x) then sin x. sin x + cos x . cos x sin2x+cos2x =1 The answer is 1.
Simplify sinx cotx cosx?
== cot(x)== 1/tan(x) = cos(x)/sin(x) Now substitute cos(x)/sin(x) into the expression, in place of cot(x) So now: sin(x) cot(x) cos(x) = sin(x) cos(x) (cos(x)/sin(x) ) sin(x) cos(x) cos(x)/sin(x) The two sin(x) cancel, leaving you with cos(x) cos(x) Which is the same as cos2(x) So: sin(x) cot(x) cos(x) = cos2(x) ===
What is sec x cos x?
sec x = 1/cos x sec x cos x = [1/cos x] [cos x] = 1
Simplyfy cos x cot x plus tan x equals?
To simplify this sort of things, it helps if, first of all, you convert everything to sines and cosines.cos x cot x + tan x (original equation)= cos (cos x / sin x) + (sin x / cos x) (convert to sin and cos)= cos2x / sin x + sin x / cos x (multiplying in the first term)= (sin x cos2x + sin x cos x) / sin x cos x (converting common denominator)= (sin x cos x) (cos x + 1) / (sin x cos x) (factoring the numerator)= cos x + 1 (cancelling factors in numerator and denominator)
