0
== cot(x)== 1/tan(x) = cos(x)/sin(x)
Now substitute cos(x)/sin(x) into the expression, in place of cot(x)
So now:
sin(x) cot(x) cos(x) = sin(x) cos(x) (cos(x)/sin(x) )
sin(x) cos(x) cos(x)/sin(x)
The two sin(x) cancel, leaving you with cos(x) cos(x)
Which is the same as cos2(x)
So:
sin(x) cot(x) cos(x) = cos2(x) ===
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How do you simplify cosx plus sinx tanx?
to simplify Cosx=Sinx Tanx you should remember your fundamental and pythagorean identities.. Cosx + Sinx Tanx Cosx + Sinx (Sinx/Cosx) <---------- From Tanx= Sinx/Cosx Cosx + Sin2x/ Cos x <------------- do the LCD Cosx (Cosx/Cosx) + Sin2x/Cosx (Cos2x+Sin2x)/Cosx 1/Cosx <--------- From Sin2x + Cos2x =1 or Secx <-------- answer Comment if you have questions...:))
Cos x plus sin x equals 0?
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No; sin2x = 2 cosx sinx
How would you find x when 0 equals 2sinxcosx-cosx?
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