treat x+y as a variable u.
dy/dx=u
dy=udx
u=x+y
du/dx=1+dy/dx
du/dx=1+x+y
du/dx=1+u
du/(1+u)=dx
dy=[u/(1+u)]du
y+C=u-ln(u+1)
y+C=x+y=ln(x+y+1)
-x+C=ln(x+y+1)
Ce-x=x+y+1
Ce-x-x-1=y
-2y square exp power -2x-1
This question has already been answered in detail and the value of x is 11/15 which when substituted into the equation results in: 12/11 = 12/11
-1
Move 3 over the right side of the equation so the equation would be x = -3. The graph of this would be a verticle line at x= -3
T/y = x/wMultiply each side by 'x':Tw/y = x
-2y square exp power -2x-1
x equals 4 over 35
(4/9) x = That's not an equation. If there were a number after the 'equals' sign, then we could calculate the value of 'x'. But as it is, there's no question there, so there's nothing to solve.
b = 14
This is an inequality equation in the form of: ii < xxii/viii which is the same as 2 < 22/8
The possibility of your next question being noob is approximately 29 over 16.
h/9=7 multiply both sides by 9 h=63
h/(-3 - 7) = 10h/-10 = 10h = -100
In order to solve for X, or find out what X equals, you need to get the X alone on one side of the equation. In this case, first you subtract the Y so that the equation becomes 5x=10-y. Then you divide both sides by 5. Now the equation is X=(10-y)/5 (or X equals the quantity of 10-y over 5).
You cannot solve this single equation. You can either change the subject so that it gives x = 12/y or xy = 12, which is the equation of a rectangular hyperbola.
To effectively use the ode23t solver in MATLAB for solving differential equations, you need to define your differential equation as a function in MATLAB and then call the ode23t solver with the appropriate inputs. Make sure to specify the initial conditions and the time span over which you want to solve the differential equation. Additionally, consider adjusting the solver options to optimize the performance and accuracy of the solution.
cross multiply to solve: 100 x 4200 = 87 Y solve for Y by doing 420,000 divided by 87, which equals 4828 (rounded off)