The browser used for posting questions on this site is rubbish. It is quite useless for mathematics since it strips out most symbols so that we cannot tell what the question is meant to be. I can only see f(x plus 1) 2x 1. I can see that it is means to be f(x+1) = 2x ~ 1but the ~ remains an unidentified operator.
From the above, you can deduce that f(x) = 2(x - 1) ~1 = 2x - 2 ~1
Similarly g(x) = 4x - 4 + 4 = 4x.
Then f(g(x) = f(4x) = 2*4x - 2 ~ 1 = 8x - 2 ~ 1.
You will need to substitute the appropriate operator for ~ and evaluate.
f(x) = √(2x -3) f(x) = (2x - 3)^(1/2) f'(x) = (1/2)[(2x - 3)^(1/2 - 1)](2) f'(x) = (2x - 3)^(-1/2) f'(x) = 1/[(2x - 3)^(1/2)] f'(x) = 1/√(2x -3)
4
Domain is the number of x values that can be used and not cause an imaginary result. Range is the number of the y values that result. In f(x)=2x-5 the range is all real numbers.
g(x) = x + 3 Then f o g (x) = f(g(x)) = f(x + 3) = sqrt[(x+3) + 2] = sqrt(x + 5)
true
y = 3x + 2x^2 + k where k is any number
5x lolzz 8)
Since g(x) is known, it helps a lot to find f(x). f(g(x)) is a new function composed by substituting x in f with g(x). For example, if g(x) = 2x + 1 and f(g(x)) = 4x2+ 4x + 1 then you you recognize that this is the square of the binomial 2x + 1, so that f(g(x)) = (f o g)(x) = h(x) = (2x + 1)2, meaning that f(x) = x2. if you have a specific example, it will be nice, because there are different ways (based on observation and intuition) to decompose a function and write it as a composite of two other functions.
please elaborate your question
That is the quotient rule and your function is.... f(x) = X^2/x+2 = (x+2)*2x-x^2*1/(x+2)^2 = 2x^2+4x-x^2/(x+2)^2 = x^2 + 4x/(x+2)^2
x = ¼x^4 + 4x + k where k can be any number
The values of x such as fgx= gfx is math. It comes down to finding the value of the letter X.
f(x) = -2x + 1; g(x) = -4x; g(f(4)) = ? Solution: (g ° f)(4) = g(f(4)) = g(-7) = 28 f(x) = -2x + 1 f(4) = -2(4) + 1 f(4) = -7 g(x) = -4x g(-7) = -4(-7) g(-7) = 28
-18
It can't be solved because its discriminant is less than zero
12
It is [(2a+2h+5) - (2a+5)]/h = 2h/h = 2