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I wasn't entirely sure what you meant, but if the problem was to find the integral of [sec(2x)-cos(x)+x^2]dx, then in order to get the answer you must follow a couple of steps:
- First you should separate the problem into three parts as you are allowed to with integration. So it becomes the integral of sec(2x) - the integral of cos(x) + the integral of x^2
- Then solve each part separately
The integral of sec(2x) is -(cos(2x)/2)
The integral of cos(x) is sin(x)
The integral of x^2 is
- Lastly you must combine them together:
-(cos(2x)/2) - sin(x) + (x^3)/3
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