1
If x - 4y = 2 and x + 4y = 2 then the only solution is when y = 0 and thus x = 2.
3x2-4x-15 = 0 (3x+5)(x-3) = 0 x = -5/3 or x = 3
2x2-7x+3 = 0 (2x-1)(x-3) = 0 x = 1/2 or x = 3
X2 - 3X - 4 = 0factored(X + 1)(X - 4)----------------X = - 1X = 4-------------------(- 1, 0) and (4, 0)================solution set of X interception points
The solution for cosec x equals 0 can be found by identifying the values of x where the cosecant function equals 0. Cosecant is the reciprocal of the sine function, so cosec x = 0 when sin x = 1/0 or sin x = undefined. This occurs at multiples of π, where the sine function crosses the x-axis. Therefore, the solutions for cosec x = 0 are x = nπ, where n is an integer.
Yes.
x = 0 or x = 2
x-2y=0 x=2y The solution set is the set of all (x,y) such that x=2y
0
(x, y) = (-6, 0)
solution: y = 0 x = -1
x - 9 = 0 x - 9 = 0 x - 9 = 0 x - 9 = 0
y = x2 + x = 0 x (X + 1) = 0 x = 0 is one solution x = -1 is the other
(x-6)(x+4) = 0 x = 6 or x = -4
x = -1 or x = 5
x = 0
It is x = -5