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Y = X2 - 4X - 5

set to zero

X2 - 4X - 5 = 0

X2 - 4X = 5

halve the linear term ( - 4 ) then square it and add that result to both sides

X2 - 4X + 4 = 5 + 4

factor on the left and gather terms together on the right

(X - 2)2 = 9

(X - 2)2 - 9 = 0

==============vertex form

(2, - 9)

======vertex

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Related Questions

How do you calculate the vertex on a function graph?

Example function.Y = X2 - 4X + 5set to 0X2 - 4X + 5 = 0X2 - 4X = - 5Now, halve the linear coefficient, square it and add it to both sidesX2 - 4X + 4 = - 5 + 4gather terms on the right and factor on the left(X - 2)2 = -1==============Vertex form.(2, - 1)=======Vertex.


What is the sum of the roots x2 - 4x - 5 0?

Their sum is 4.


What is the vertex of y-2x2-4x-5?

2x2= 4


What are the coordinates of the vertex for y equals -x2 plus 4x-9?

You can work this out by taking the derivative of the equation with respect to y, and finding where that derivative (ie. the slope of the curve's tangent) equals 0: y = -x2 + 4x - 9 ∴ dy/dx = -2x + 4 Let dy/dx = 0: 0 = -2x + 4 ∴ x = 2 Now find the corresponding y co-ordinate by plugging that value for x into the original equation: y = -(2)2 + 4(2) - 9 ∴ y = - 4 + 8 - 9 ∴ y = -5 So the vertex of that parabola is located at the point (2, -5).


What are the coordinates of the fourth vertex of a rectangle that has three vertices at 4 -5 and 4 -3 and 5 -3?

The vertex is at (5, -5).


What is a polynomial function that has zeroes of -5 2 plus i and 2-i?

Since the polynomial has three zeroes it has a degree of 3. So we have:(x - -5)[x - (2 + i)][x - (2 - i)]= (x + 5)[(x - 2) - i][(x - 2) + i]= (x + 5)[(x - 2)2 - i2]= (x + 5)[x2 - 2(x)(2) + 22 - (-1)]= (x + 5)(x2 - 4x + 4 + 1)= (x + 5)(x2 - 4x + 5)= x(x2 - 4x + 5) + 5(x2 - 4x + 5)= x3 - 4x2 + 5x + 5x2 - 20x + 25= x3 + x2 - 15x + 25Thus,P(x) = x3 + x2 - 15x + 25


What number must you add to complete the square x2 plus 4x equals 5?

Add 4 to both sides. To complete the square, take half the x coefficient into the bracket: (x + 4/2)2 = (x + 2)2 = x2 + 4x + 4 Comparing with the original, need to add 4 to both sides of x2 + 4x = 5: (x2 + 4x) + 4 = (5) + 4 ⇒ x2 + 4x + 4 = 9 ⇒ (x + 2)2 = 9


What is x2-4x-5 equals?

X2 - 4X - 5 as an expression, or equation is factorable when the question, what two factors of - 5 add to - 4 is answered ( X + 1)(X - 5) X = - 1 ------------and X = 5 ---------------


What roots value x2-4x 5?

Assuming the missing operator before the final 5 is subtract, then: x2 - 4x - 5 = (x + 1) (x - 5) ⇒ x = -1 or 5. If it is add, there are no real root solution. The solution to the latter case is: x2 - 4x + 5 = (x - 2 - i)(x - 2 + i) ⇒ x = 2 + i or x = 2 - i.


What is the factor of x2-4x-5?

f(x) = x2-4x-5 = x2-5x+x-5 = x(x-5)+1(x-5) = (x+1)(x-5) Factors of f(x) are (x+1) and (x-5).


How do you factor x2 plus 4x-5 equals 0?

X2 + 4X - 5 = 0 what two factor of - 5 add up to 4? (X - 1)(X + 5) ----------------- ( so, X = 1 and X = - 5 )


How do you simplify the equation x2 plus 4x-5 divided by x plus 5 I am stuck?

x+5 is a factor of x2+4x-5 use synthetic division to learn that the other factor is x-1