0
Y = X2 - 4X - 5
set to zero
X2 - 4X - 5 = 0
X2 - 4X = 5
halve the linear term ( - 4 ) then square it and add that result to both sides
X2 - 4X + 4 = 5 + 4
factor on the left and gather terms together on the right
(X - 2)2 = 9
(X - 2)2 - 9 = 0
==============vertex form
(2, - 9)
======vertex
What else can I help you with?
What is the vertex for the parabola y equals x squared plus 4x plus 5?
The vertex of a parabola is the minimum or maximum value of the parabola. To find the maximum/minimum of a parabola complete the square: x² + 4x + 5 = x² + 4x + 4 - 4 + 5 = (x² + 4x + 4) + (-4 + 5) = (x + 2)² + 1 As (x + 2)² is greater than or equal to 0, the minimum value (vertex) occurs when this is zero, ie (x + 2)² = 0 → x + 2 = 0 → x = -2 As (x + 2)² = 0, the minimum value is 0 + 1 = 1. Thus the vertex of the parabola is at (-2, 1).
Find a counterexample if x equals -5 then X2 equals 25?
In ordinary mathematics, assuming that x = X and that X2 denotes x2 or x-squared, there cannot be a counterexample since the statement is TRUE. However, there are two assumptions made that could be false and so could give rise to counterexamples. 1. x is not the same as X. If, for example X = 4x then X = -20 so that X2 = 400. 2a. X2 is not X2 but X times 2. In that case X2 = -10. 2b. X2 is x2 modulo 7, for example. Then X2 = 4.
What is -4x divide by 1?
-5
What is 3x plus 5 equals 4x-10?
3x+5= 4x-10+10 +103x+15= 4x-3x -3x15=X
2x plus 5 equals 7-4x?
2x + 5 = 7 - 4x ie 2x + 4x = 7 - 5 ie 6x = 2 x = one third.
How do you calculate the vertex on a function graph?
Example function.Y = X2 - 4X + 5set to 0X2 - 4X + 5 = 0X2 - 4X = - 5Now, halve the linear coefficient, square it and add it to both sidesX2 - 4X + 4 = - 5 + 4gather terms on the right and factor on the left(X - 2)2 = -1==============Vertex form.(2, - 1)=======Vertex.
What is the vertex of y-2x2-4x-5?
2x2= 4
What is the sum of the roots x2 - 4x - 5 0?
Their sum is 4.
What are the coordinates of the fourth vertex of a rectangle that has three vertices at 4 -5 and 4 -3 and 5 -3?
The vertex is at (5, -5).
What is a polynomial function that has zeroes of -5 2 plus i and 2-i?
Since the polynomial has three zeroes it has a degree of 3. So we have:(x - -5)[x - (2 + i)][x - (2 - i)]= (x + 5)[(x - 2) - i][(x - 2) + i]= (x + 5)[(x - 2)2 - i2]= (x + 5)[x2 - 2(x)(2) + 22 - (-1)]= (x + 5)(x2 - 4x + 4 + 1)= (x + 5)(x2 - 4x + 5)= x(x2 - 4x + 5) + 5(x2 - 4x + 5)= x3 - 4x2 + 5x + 5x2 - 20x + 25= x3 + x2 - 15x + 25Thus,P(x) = x3 + x2 - 15x + 25
What are the coordinates of the vertex for y equals -x2 plus 4x-9?
You can work this out by taking the derivative of the equation with respect to y, and finding where that derivative (ie. the slope of the curve's tangent) equals 0: y = -x2 + 4x - 9 ∴ dy/dx = -2x + 4 Let dy/dx = 0: 0 = -2x + 4 ∴ x = 2 Now find the corresponding y co-ordinate by plugging that value for x into the original equation: y = -(2)2 + 4(2) - 9 ∴ y = - 4 + 8 - 9 ∴ y = -5 So the vertex of that parabola is located at the point (2, -5).
What number must you add to complete the square x2 plus 4x equals 5?
Add 4 to both sides. To complete the square, take half the x coefficient into the bracket: (x + 4/2)2 = (x + 2)2 = x2 + 4x + 4 Comparing with the original, need to add 4 to both sides of x2 + 4x = 5: (x2 + 4x) + 4 = (5) + 4 ⇒ x2 + 4x + 4 = 9 ⇒ (x + 2)2 = 9
What is x2-4x-5 equals?
X2 - 4X - 5 as an expression, or equation is factorable when the question, what two factors of - 5 add to - 4 is answered ( X + 1)(X - 5) X = - 1 ------------and X = 5 ---------------
What are the coordinates of the vertex of the parabola described by the equation below?
The coordinates will be at the point of the turn the parabola which is its vertex.
What roots value x2-4x 5?
Assuming the missing operator before the final 5 is subtract, then: x2 - 4x - 5 = (x + 1) (x - 5) ⇒ x = -1 or 5. If it is add, there are no real root solution. The solution to the latter case is: x2 - 4x + 5 = (x - 2 - i)(x - 2 + i) ⇒ x = 2 + i or x = 2 - i.
What is the factor of x2-4x-5?
f(x) = x2-4x-5 = x2-5x+x-5 = x(x-5)+1(x-5) = (x+1)(x-5) Factors of f(x) are (x+1) and (x-5).
How do you factor x2-4x 5?
If that's -5 the answer is (x - 5)(x + 1)
