x + 2y = 27
2x - y = 19
y = 2x - 19
x + 2(2x - 19) = 27
x + 4x - 38 = 27
5x = 65
x = 13
y = 2(13) - 19
y = 7
Add the two equations together. This will give you a single equation in one variable. Solve this - it should give you two solutions. Then replace the corresponding variable for each of the solutions in any of the original equations.
3x - 12 = 10x - 15 - 6x -10 3x - 12 = 4x -25 3x + 13 = 4x 13 = 4x - 3x 13 = x None?
so, if 2 minus Ln times 3 minus x equals 0, then 2 minus Ln times 3 equals x, therefore 2 minus Ln equals x divided by three, so Ln + X/3 = 2 therefore, (Ln + [X/3]) = 1
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc.
I'll do ya one better - 12 plus 8 equals what?
x = 4 and y = 7 which will satisfy both equations
They are identities because they are true for ALL values of w and x.
+ (plus) - (minus) / (divide) * (multiply) ^ (power) = (equals)
{-1,-2}
That depends what the values of k and b are.
No.
16
Without knowing the plus or minus values of the given terms and without any equality signs it can't be considered as a system of equations.
If a equals 3 and b equals minus 5 then a minus b equals what
This cannot be solved. If you have 2 unknowns (a,b) then you must have 2 equations.
The solutions are: x = -2 and y = 4
That is an impossible equation, because it is stating that m has two values.