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d/dx (e-x) = -e-x

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14y ago

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Related Questions

What is the first derivative of e raised to the power of x?

The first derivative of e to the x power is e to the power of x.


What is the derivative of e negative x?

- e^- X


What is the integral of e to the negative x?

-e^(-x) or negative e to the negative x this is because you multiply the function (e) by: 1 / (the derivative of the power ... in this case: -1) e^(-x) * (1/-1) = -e^(-x) Don't forget to add your constant!


What is the derivative of e to the power of -2 times x?

e^(-2x) * -2 The derivative of e^F(x) is e^F(x) times the derivative of F(x)


What is the integral to negative e to the power x?

The integral of (-e^x) with respect to (x) is (-e^x + C), where (C) is the constant of integration. This represents the family of functions whose derivative is (-e^x).


What is the derivative of 1 divided by x to the third power?

1 divided by x to the third power equals x to the negative third. The derivative of x to the negative third is minus three x to the negative fourth.


What is the derivative of e to the power of x?

The derivative of ex is ex


What is the derivative of x to the power of e?

e^[ln(x^2)]=x^2, so your question is really, "What is the derivative of x^2," to which the answer is 2x.


What is the derivative of e the the power ln x?

y = e^ln x using the fact that e to the ln x is just x, and the derivative of x is 1: y = x y' = 1


What is the derivative of e to the power ln x squared?

e^[ln(x^2)]=x^2, so your question is really, "What is the derivative of x^2," to which the answer is 2x.


How do you do derivative 27ex?

I assume you mean 27 times e to the power x. 1) You take out the constant out. So, the derivative is 27 times the derivative of (e to the power x).2) You use the rule for the exponential function.


What is the derivative of e to the power of 2lnx?

Your expression simplifies to just x^2 {with the restriction that x > 0}. The derivative of x^2 is 2*x

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