- e^- X
e^(-2x) * -2 The derivative of e^F(x) is e^F(x) times the derivative of F(x)
y = e^ln x using the fact that e to the ln x is just x, and the derivative of x is 1: y = x y' = 1
Your expression simplifies to just x^2 {with the restriction that x > 0}. The derivative of x^2 is 2*x
2.71828183 ==So the derivative of a constant is zero.If you have e^x, the derivative is e^x.
The first derivative of e to the x power is e to the power of x.
- e^- X
-e^(-x) or negative e to the negative x this is because you multiply the function (e) by: 1 / (the derivative of the power ... in this case: -1) e^(-x) * (1/-1) = -e^(-x) Don't forget to add your constant!
e^(-2x) * -2 The derivative of e^F(x) is e^F(x) times the derivative of F(x)
1 divided by x to the third power equals x to the negative third. The derivative of x to the negative third is minus three x to the negative fourth.
The derivative of ex is ex
e^[ln(x^2)]=x^2, so your question is really, "What is the derivative of x^2," to which the answer is 2x.
y = e^ln x using the fact that e to the ln x is just x, and the derivative of x is 1: y = x y' = 1
e^[ln(x^2)]=x^2, so your question is really, "What is the derivative of x^2," to which the answer is 2x.
I assume you mean 27 times e to the power x. 1) You take out the constant out. So, the derivative is 27 times the derivative of (e to the power x).2) You use the rule for the exponential function.
Your expression simplifies to just x^2 {with the restriction that x > 0}. The derivative of x^2 is 2*x
The derivative of cos(x) is negative sin(x). Also, the derivative of sin(x) is cos(x).