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What else can I help you with?
What is the derivative of square root of x?
sqrt(x) = x^(1/2) The derivative is (1 / 2) * x^(-1 / 2) = 1 / (2 * x^(1 / 2)) = 1 / (2 * sqrt(x))
What is the anti derivative of the square root of 1-x2?
-1
What is the derivative of y equals square root of 8x plus square root of 4x?
y=(8x).5 + (4x).5 = (2+2sqrt(2))x.5 y'=(1 + sqrt(2))/sqrt(x)
What is the derivative of 4 over x?
4/x can be written as 4x-1 (the power of negative 1 means it is the denominator of the fraction) 4*-1 = -4 Therefore, the derivative is -4x-2
What is the derivative of e to the power of -2 times x?
e^(-2x) * -2 The derivative of e^F(x) is e^F(x) times the derivative of F(x)
What is the derivative of the square root of 2?
The derivative of sqrt(2) is zero.
What is the derivative of 3 divided by square root x?
To find the derivative of ( \frac{3}{\sqrt{x}} ), we can rewrite it as ( 3x^{-\frac{1}{2}} ). Using the power rule, the derivative is ( -\frac{3}{2} x^{-\frac{3}{2}} ). This can also be expressed as ( -\frac{3}{2\sqrt{x^3}} ).
What is the derivative of x plus root x?
Derivative of x = 1, and since sqrt(x) = x^(1/2), derivative of x^(1/2) = (1/2)*(x^(-1/2))Add these two terms together and derivative = 1 + 1/(2*sqrt(x))
What is the derivative of square root of x?
sqrt(x) = x^(1/2) The derivative is (1 / 2) * x^(-1 / 2) = 1 / (2 * x^(1 / 2)) = 1 / (2 * sqrt(x))
What is the first derivative of 3x- 4sq root 2?
3x - 4 sqrt(2)The first derivative with respect to 'x' is 3.
What is the antiderivative of sqrtx plus 4ex minus sinx?
The anti-derivative of sqrt(x) : sqrt(x)=x^(1/2) The anti-derivative is x^(1/2+1) /(1/2+1) = (2/3) x^(3/2) The anti-derivative is 4e^x is 4 e^x ( I hope you meant e to the power x) The anti-derivative of -sin(x) is cos(x) Adding, the anti-derivative is (2/3) x^(3/2) + 4 e^x + cos(x) + C
What does formula of derivative of an inverse allows you to do?
The formula for the derivative of an inverse (finv)' = 1/(f' o (finv)) allows you get a formula for the derivative of the inverse of any function that you already know the derivative of. For example: What is the derivative of sqrt(x)? You could figure this out using the definition of the derivative, but it is complicated. You already know that the derivative of x2 is 2x. So let f = x2; finv = sqrt(x), f' = 2x. This gives: (sqrt(x))' = 1/(2 sqrt(x)). Now you have derived a "square root rule" with almost no work.
Is there a sequence to finding multiple derivatives of the square root of x?
sqrt(X) is also X^1/2 use power rule 1/2X^-1/2 ( first derivative ) -1/4X^-3/2 ( second derivative ) and so on
What is the derivative of square root of 5x?
Derivative with respect to 'x' of (5x)1/2 = (1/2) (5x)-1/2 (5) = 2.5/sqrt(5x)
What is the derivative of the quantity 3 times x plus 1 to the one half power?
Take the derivative of (3x+1)1/2First use the power rule on the entire function, then multiply it by the derivative of the inside:(1/2)(3x-1)-1/2(3) = (3/2)(3x-1)-1/2which can also be written as3/(2sqrt(3x-1))(sqrt stands for square root)
How do you rationalize the denominator expressin 15 over square root of 2?
By using a form of 1, sqrt(2)/sqrt(2),and multiplying. 15/sqrt(2) * sqrt(2)/sqrt(2) = 15sqrt(2)/2 -------------------
What is the square root 3 plus square root 6 over square root 2?
Because questions can't use punctuation the question is ambiguous. Two possible interpretations of the question, with answers are given below:sqrt(3) + sqrt(6) / sqrt(2) = sqrt(3) + sqrt(6/2) = sqrt(3) + sqrt(3) = 2*sqrt(3)The more likely question is:[sqrt(3) + sqrt(6)]/sqrt(2)Multiply numberator and denominator by sqrt(2) to give[sqrt(2)*sqrt(3) + sqrt(2)*sqrt(6)]/[sqrt(2)*sqrt(2)]=[sqrt(2)*sqrt(3) + 2*sqrt(3)]/2 since sqrt(2)*sqrt(2) = 2= sqrt(3)*[sqrt(2)+1]/2AnswerSquare root three plus square root six is square root 9 over square root two. But nine can be factored out to a perfect three so you would have 3 over square root two.
