0
x5lnx?
d/dx (uv)=u*dv/dx+v*du/dx
d/dx (x5lnx)=x5*[d/dx(lnx)]+lnx*[d/dx(x5)]
-The derivative of lnx is:
d/dx(lnu)=(1/u)*[d/dx(u)]
d/dx(lnx)=(1/x)*[d/dx(x)]
d/dx(lnx)=(1/x)*[1]
d/dx(lnx)=(1/x)
-The derivative of x5 is:
d/dx (xn)=nxn-1
d/dx (x5)=5x5-1
d/dx (x5)=5x4
d/dx (x5lnx)=x5*[1/x]+lnx*[5x4]
d/dx (x5lnx)=[x5/x]+5x4lnx
d/dx (x5lnx)=x4+5x4lnx
Still curious? Ask our experts.
Chat with our AI personalities
Taiga
Devin
LaoAdd your answer:
Earn +20 pts
Prove that a constant vector always has a perpendicular derivative?
A dot A = A2 do a derivative of both sides derivative (A) dot A + A dot derivative(A) =0 2(derivative (A) dot A)=0 (derivative (A) dot A)=0 A * derivative (A) * cos (theta) =0 => theta =90 A and derivative (A) are perpendicular
What is the derivative of e7x?
The derivative of e7x is e7 or 7e.The derivative of e7x is 7e7xThe derivative of e7x is e7xln(7)
What is the derivative of square root of 2?
the derivative is 0. the derivative of a constant is always 0.
What is the derivative of 4x?
Derivative of 4x is 4.
What is the derivative for 3x-1?
The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.
