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What is the derivative of x4?
X^4 ? 4x^3
What is the derivative of 4 over x?
4/x can be written as 4x-1 (the power of negative 1 means it is the denominator of the fraction) 4*-1 = -4 Therefore, the derivative is -4x-2
What is the anti-derivative of 5x-4?
9
What is the vertex of the graph of the function y equals x2-4x plus 3?
To find the extreme value of the parabola y = x2 - 4x + 3 ...(1) Take the derivative of the equation.y = x2 - 4x + 3y' = 2x - 4(2) Set the derivative = 0 and solve for x.y' = 2x - 40 = 2x - 42x = 4x = 4/2x = 2(3) Plug this x value back into the original equation to find the associated y coordinate.x = 2y = x2 - 4x + 3y = (2)2 - 4(2) + 3y = 4 - 8 + 3y = -1So the vertex is at (2, -1).
What is the derivative of y equals square root of 8x plus square root of 4x?
y=(8x).5 + (4x).5 = (2+2sqrt(2))x.5 y'=(1 + sqrt(2))/sqrt(x)
What is the derivative of 2x-squared plus 4x plus 8?
The derivative of 2x2 + 4x + 8 is 4x+4.
What is the derivative of the square root of 4x plus 25?
I believe you are asking: What is the derivative (d/dx) of (4x+25)^0.5 If this is indeed the case, the derivative d((4x+25)^0.5)/dx = 0.5*(4x+25)^-0.5*4 = 2(4x+25)^-0.5 That is, 2 times the quantity (4x+25) to the negative 1/2 power.
What is the second derivative of x to the fourth power?
d/dx(X^4) = 4X^3 ( first derivative ) d/dx(4X^3) = 12X^2 ( second derivative )
What is the second derivative of 4lnx?
-4x^-2
What is the derivative of 4x-X2?
2
What is the derivative of x4?
X^4 ? 4x^3
The total derivative of 2x2 plus 7?
4x
How do you find the derivative of x4?
The derivative of x^n is nx^(n-1) any n. The derivative of x^4 is 4x^3.
What is the derivative of cot4x?
Chain rule. -4csc^2(4X)
What is the derivative of 4 over x?
4/x can be written as 4x-1 (the power of negative 1 means it is the denominator of the fraction) 4*-1 = -4 Therefore, the derivative is -4x-2
Derivative of 2x squared?
d/dx 2x^2 = 4x
What is the derivative of y equals the quantity 2x plus 5 raised to 8 plus 4x all raised to3?
I am interpreting this as: Find the derivative of: y=((2x+5)8+4x)3 To find the derivative (y'), the chain rule must be applied. The "outermost" function of this compound function is t3 (t being an arbitrary quantity). The derivative of t3 is 3t2 * dt, where "dt" is the derivative of the quantity "t". Applying this, we arrive at a working definition of y': y' = 3((2x+5)8+4x)2(derivative of (2x+5)8+4x) The derivative of (2x+5)8+4x is found using basic derivative definitions and the chain rule again: 8(2x+5)7(2)+4 = 16(2x+5)7+4 So now we can write y' again: y'= 3((2x+5)8+4x)2(16(2x+5)7+4) = 48((2x+5)8+4x)2((2x+5)7+4) This can be further simplified, but this is an arduous process. If you need further simplification, feel free to contact me via private message.
