This is technically a partial derivative, represented as ∂(20xy)/∂x. The way to calculate this is simple, treat y as a constant, like 20 is in this case. Therefore, the expression is simplified to 20*y*d(x)/dx. d(x)/dx is just 1, so the answer is 20y.
If it is with respect to t: 1 If it is with respect to some other variable (x for example): (dt)/(dx), which is literally read "the derivative of t with respect to x"
If y = 3x +- 1, the derivative with respect to x is y' = 3.
∫ d/dx f(x) dx = f(x) + C C is the constant of integration.
If x is a function of time, t, then the second derivative of x, with respect to t, is the acceleration in the x direction.
The derivative of 10x with respect to x is 10 and 25y with respect to y is 25. If it is 10x25y, then use the chain rule. 10x 25y = 10*25y + 10x*25y' = 250y + 250xy'
The derivative with respect to 'x' is 4y3 . The derivative with respect to 'y' is 12xy2 .
2*2*5*x*y
The derivative with respect to 'x' of sin(pi x) ispi cos(pi x)
If it is with respect to t: 1 If it is with respect to some other variable (x for example): (dt)/(dx), which is literally read "the derivative of t with respect to x"
The derivative, with respect to x, is -x/sqrt(1-x2)
If by "2aXaXa", you actually mean "2a3", then the derivative with respect to a is 6a2. On the other hand, if you actually mean "2a3X2", then it's derivative with respect to X would be 6a2X2(da/dx) + 4a3X. If "a" is simply a constant though, then it's derivative is 4a3X
2 times 2 times 5 times x times y = 20xy
The third derivative of the function x with respect to time is the rate of change of the acceleration of x with respect to time. It is denoted as d3x/dt3.
well if you're finding the derivative with respect to x, it would be -tx^(-t-1)
2,5,10,x
d/dx ∫ f(x) dx = f(x)
Yes, the derivative of xi with respect to x equals i. Is that what you were trying to ask?